ElectrochemistryBalancing Redox Reactions by Ion-Electron Method1Choose the best answerFor the reduction half-reaction MnO₄⁻ → Mn²⁺ in acidic medium, the number and position of electrons are:A5e⁻ on the rightB5e⁻ on the leftC3e⁻ on the rightD3e⁻ on the left Like 0 Discuss 0Share