ElectrochemistryBalancing Redox Reactions by Ion-Electron Method1Choose the best answerTo balance the reduction half-reaction: MnO₂ + 4H⁺ → Mn²⁺ + 2H₂O electrons should be added as:A2e⁻ on the left sideB2e⁻ on the right sideC4e⁻ on the left sideD4e⁻ on the right side Like 3 Discuss 0Share
ElectrochemistryBalancing Redox Reactions by Ion-Electron Method2Choose the best answerFor the reduction half-reaction MnO₄⁻ → Mn²⁺ in acidic medium, the number and position of electrons are:A5e⁻ on the rightB5e⁻ on the leftC3e⁻ on the rightD3e⁻ on the left Like 0 Discuss 0Share
ElectrochemistryBalancing Redox Reactions by Ion-Electron Method3Choose the best answerTo balance the half-reaction MnO₂ + 4H⁺ → Mn²⁺ + 2H₂O, electrons must be added as:A2e⁻ on the left sideB2e⁻ on the right sideC4e⁻ on the left sideD4e⁻ on the right side Like 0 Discuss 0Share