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Correct Answer: D) Fe²⁺
Mg²⁺ = [Ne] → 0 unpaired Ti³⁺ = [Ar] 3d¹ → 1 unpaired V³⁺ = [Ar] 3d² → 2 unpaired Fe²⁺ = [Ar] 3d⁶ → 4 unpaired electrons Therefore, Fe²⁺ has the maximum.