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Correct Answer: A) 3
Valid combinations must satisfy ℓ ≤ n − 1. For n + ℓ = 6: n = 4, ℓ = 2 → 4d n = 5, ℓ = 1 → 5p n = 6, ℓ = 0 → 6s Therefore, 3 subshells are possible.