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Stoichiometry Mole–Volume Stoichiometry

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0.25 mol N₂ reacts with excess H₂: N₂ + 3H₂ → 2NH₃ The volumes of H₂ consumed and NH₃ produced at STP (273 K and 1 atm) are respectively:

Verified Answer & Explanation⌄

Correct Answer: A) 16.8 L and 11.2 L

Concept Explanation

0.25 mol N₂ requires 0.75 mol H₂ and produces 0.50 mol NH₃. H₂ volume = 0.75 × 22.4 = 16.8 L. NH₃ volume = 0.50 × 22.4 = 11.2 L.

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