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Stoichiometry Mole Concept and Number of Atoms

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How many carbon atoms are present in 18 g glucose, C₆H₁₂O₆?

Verified Answer & Explanation⌄

Correct Answer: D) 3.6 × 10²³

Concept Explanation

18 g glucose = 0.10 mol. Carbon atoms = 0.10 × 6 = 0.60 mol C atoms. Number = 0.60 × 6.022 × 10²³ ≈ 3.6 × 10²³.

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