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Xi MDCAT XI Complete Chemistry Grand Test #Cell Potential #Electrochemistry

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For E°(Fe²⁺/Fe) = −0.44 V and E°(Sn²⁺/Sn) = −0.14 V, calculate E°cell for Fe²⁺ + Sn → Fe + Sn²⁺.

Verified Answer & Explanation⌄

Correct Answer: C) −0.30 V

Concept Explanation

For the reaction as written, Fe²⁺ is reduced and Sn is oxidized. E°cell = E°cathode − E°anode = −0.44 − (−0.14) = −0.30 V.

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