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Verified Answer & Explanation⌄

Correct Answer: B) 22.4 L

Concept Explanation

8.0 g CH₄ = 0.50 mol. 0.50 mol CH₄ requires 1.0 mol O₂. At 273 K and 1 atm, 1 mol O₂ occupies about 22.4 L.

Topic: Mass–Volume StoichiometryPractice more Mass–Volume Stoichiometry MCQs →