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Verified Answer & Explanation⌄

Correct Answer: B) 11.2 L

Concept Explanation

4 g CH₄ = 4/16 = 0.25 mol. O₂ required = 0.25 × 2 = 0.50 mol. Volume = 0.50 × 22.4 = 11.2 L.

Topic: Mass–Volume StoichiometryPractice more Mass–Volume Stoichiometry MCQs →