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Stoichiometry Mass–Volume Stoichiometry

1

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What volume of NH₃ at STP (273 K and 1 atm) is required to react completely with 49 g H₂SO₄? 2NH₃ + H₂SO₄ → (NH₄)₂SO₄

Verified Answer & Explanation⌄

Correct Answer: B) 22.4 L

Concept Explanation

49 g H₂SO₄ = 0.50 mol. 0.50 mol H₂SO₄ requires 1.0 mol NH₃. At 273 K and 1 atm, 1 mol gas occupies about 22.4 L. Therefore, NH₃ required = 22.4 L.

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