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Verified Answer & Explanation⌄

Correct Answer: C) 0.224 L

Concept Explanation

1.0 g CaCO₃ = 0.010 mol. Therefore, CO₂ produced = 0.010 mol = 0.224 L at STP.

Topic: Mass–Volume StoichiometryPractice more Mass–Volume Stoichiometry MCQs →