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Verified Answer & Explanation⌄

Correct Answer: C) 1.12 L

Concept Explanation

3.2 g O₂ = 3.2/32 = 0.10 mol. CH₄ required = 0.10/2 = 0.05 mol. Volume = 0.05 × 22.4 = 1.12 L.

Topic: Mass–Volume StoichiometryPractice more Mass–Volume Stoichiometry MCQs →