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Stoichiometry Mass–Mass Stoichiometry

1

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What mass of O₂ is required to convert 1.35 g Al completely into Al₂O₃? 4Al + 3O₂ → 2Al₂O₃

Verified Answer & Explanation⌄

Correct Answer: D) 1.2 g

Concept Explanation

1.35 g Al = 1.35/27 = 0.05 mol. O₂ required = (3/4) × 0.05 = 0.0375 mol. Mass = 0.0375 × 32 = 1.2 g.

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