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Correct Answer: A) NH₄Cl
Moles of NH₄Cl ≈ 100/53.5 = 1.87 mol. Moles of Ca(OH)₂ ≈ 100/74 = 1.35 mol. 1.35 mol Ca(OH)₂ requires 2.70 mol NH₄Cl, but only 1.87 mol is available. Therefore, NH₄Cl is the limiting reagent.