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Stoichiometry Limiting Reagent and Excess Reactant

1

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14 g N₂ reacts with 6 g H₂: N₂ + 3H₂ → 2NH₃ How much H₂ remains unreacted?

Verified Answer & Explanation⌄

Correct Answer: A) 1.5 mol

Concept Explanation

14 g N₂ = 0.50 mol. H₂ required = 0.50 × 3 = 1.50 mol. 6 g H₂ = 3.0 mol. H₂ remaining = 3.0 − 1.5 = 1.5 mol.

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