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KMU MDCAT 2024 Chemistry #Mole Calculations #Stoichiometry

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How many moles of NaCl are produced from 16.5g of HCl, according to the neutralization reaction? HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l) (KMU MDCAT 2024)

Verified Answer & Explanation⌄

Correct Answer: B) 0.452

Concept Explanation

Moles of HCl = 16.5/36.5 ≈ 0.452 mol. The reaction ratio HCl:NaCl is 1:1, so 0.452 mol NaCl forms.

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