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Correct Answer: D) 60 mL C₂H₂, 80 mL CO₂ and 40 mL H₂O
5 volumes O₂ react with 2 volumes C₂H₂. 100 mL O₂ consumes: (2/5) × 100 = 40 mL C₂H₂. C₂H₂ remaining = 100 − 40 = 60 mL. Products: CO₂ = 80 mL H₂O vapour = 40 mL.