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Chemical Equilibrium Active Mass

1

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The active mass of 64 g of HI present in a 2.0 dm³ flask is approximately:

Verified Answer & Explanation⌄

Correct Answer: D) 0.25 mol dm⁻³

Concept Explanation

Moles of HI = 64/128 = 0.50 mol; concentration = 0.50/2.0 = 0.25 mol dm⁻³.

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