Aldehydes and KetonesPreparation from Calcium Salts of Carboxylic Acids1Choose the best answerWhich combination is correctly matched?ACalcium formate → Methanal; Calcium acetate → Propanone; Calcium formate + calcium acetate → EthanalBCalcium formate → Propanone; Calcium acetate → Ethanal; Calcium formate + calcium acetate → MethanalCCalcium formate → Methanal; Calcium acetate → Ethanal; Calcium formate + calcium acetate → PropanoneDCalcium formate → Ethanal; Calcium acetate → Propanone; Calcium formate + calcium acetate → Methanal Like 0 Discuss 0Share