ARMCQs DIGITAL STUDY NOTES
Chapter 1: Fundamentals of Chemistry
Definition of Chemistry
Definition
Chemistry is the branch of science that studies the composition, structure, properties and changes of matter.
Understand it simply
Chemistry helps us answer three questions: What is a substance made of? What is it like? How can it change?
Understand the terms
Term | Meaning | Example |
|---|---|---|
Matter | Anything with mass that occupies space | Air, water, iron |
Composition | What a material contains and in what proportion | H₂O contains H and O in a 2 : 1 atom ratio |
Structure | How particles are joined and arranged | One O atom bonded to two H atoms in water |
Property | A characteristic of a substance | Colour, density, ability to burn |
Mass describes how much matter an object contains; volume is the space it occupies. Density = mass/volume. A chemical bond is an attraction holding atoms or ions together.
Properties and changes
Physical | Chemical |
|---|---|
A physical property is observed without forming a new substance: colour or melting point | A chemical property describes the ability to react: iron’s ability to rust |
A physical change retains chemical identity: ice → water | A chemical change forms new substances: iron → rust |
Melting point is the temperature at which a solid becomes liquid at a given pressure. To identify a chemical change, ask: “Has a new substance formed?” Being easy or hard to reverse does not decide the answer.
Importance in daily life
Area | Application |
|---|---|
Food | Cooking; digestion—breaking food into absorbable substances; preservation—delaying spoilage |
Health | Developing and preparing medicines |
Agriculture | Fertilizers supply nutrients needed for plant growth |
Cleaning | Soaps and detergents remove dirt and grease |
Water | Treatment removes impurities and harmful microorganisms (microscopic organisms) |
Industry | Manufacture of glass, cement, plastics, fibres and ceramics |
Scientists observe, suggest explanations and test them. The word science comes from the Latin scientia, meaning knowledge.
Atom
Definition
An atom is the smallest unit of an element that retains its chemical identity.
Understand it simply
Every element has its own kind of atom. The number of protons tells us which element it is.
Example
One copper atom is still copper. Copper atoms are identified by their proton number. An electron on its own is not a smaller copper atom.
Structure
Subatomic means smaller than an atom. The nucleus is the tiny centre. It contains protons and usually neutrons. Electrons are outside the nucleus.
Particle | Relative charge | Location | Approximate relative mass |
|---|---|---|---|
Proton, p⁺ | +1 | Nucleus | 1 |
Neutron, n | 0 | Nucleus | 1 |
Electron, e⁻ | −1 | Outside nucleus | 1/1836 |
Inside a carbon-12 atom
Change the model · explore the parts
Choose a heavier isotope of the same element. What must change?
Choose what you expect, then test it below. You can explore without answering first.
Start with the selected neutral atom. Compare its proton, neutron and electron counts.
Choose the isotope with the next higher mass number. Read A, Z and the three particle counts.Changing the isotope changes neutrons and mass number. Proton number and the neutral atom’s electron count stay fixed. Shell rings are a model, not literal paths.
Change the controls to see the result. Choose Explore diagram parts for a guided explanation.
View complete static diagram
Key points
Every oxygen atom has 8 protons.
Almost all the atom’s mass is in its tiny nucleus.
Electrons take part in ordinary chemical bonds.
Helium exists as separate atoms. Oxygen usually exists as O₂ molecules.
Ordinary hydrogen, ¹H, has 1 proton and no neutron.
Why neutral?
A neutral atom has equal numbers of protons and electrons. In carbon, 6 positive charges balance 6 negative charges. The overall charge is zero. Opposite charges attract. Like charges repel.
Remember: O is an oxygen atom; O₂ is an oxygen molecule containing two atoms.
Molecule
Definition
A molecule is an electrically neutral group of two or more chemically bonded atoms.
Understand it simply
Atoms join by chemical bonds to make a molecule. Count the atoms to see how many are joined.
Examples
O₂ has 2 oxygen atoms. H₂O has hydrogen and oxygen atoms. A small lower-right number is a subscript. It counts atoms. CO₂ has 1 C and 2 O atoms: 3 atoms altogether.
Classification
Basis | Type | Meaning and examples |
|---|---|---|
Atomicity: atoms per molecule | Diatomic | 2 atoms: H₂, N₂, O₂, Cl₂, Br₂, I₂ |
Atomicity | Triatomic | 3 atoms: H₂O, CO₂, O₃ |
Atomicity | Polyatomic | More than 2 atoms: NH₃, CH₄, P₄, S₈; includes triatomic molecules |
Composition | Homoatomic | One element: O₂, O₃, P₄, S₈ |
Composition | Heteroatomic | Different elements: H₂O, CO₂, NH₃ |
One molecule can fit two groups. H₂O is triatomic because it has 3 atoms. It is also heteroatomic because it contains different elements. O₃ has 3 atoms of the same element, so it is triatomic and homoatomic.
Monatomic means one atom. He, Ne, Ar, Kr, Xe and Rn exist as individual atoms. They are often called monatomic species.
Build a clear picture of each molecule
Choose a stage. Press Play to observe the movement.
He. He is one atom: a monatomic species, not a bonded molecule.
Schematic model. Colours distinguish particles; sizes and speeds are illustrative. Animation starts only when you press Play.
View reference diagram
Count all the atoms, not just the different symbols. NH₃ contains 2 elements but 4 atoms.
Element
Definition
An element is a pure substance whose atoms have the same number of protons. It cannot be broken into simpler substances by ordinary chemical reactions.
Understand it simply
An element contains only one kind of atom. Oxygen gas is an element because every atom in it is oxygen.
Example
Copper and oxygen are elements. O₂ still counts as an element because all its atoms are oxygen.
Types of elements
Type | General properties | Examples |
|---|---|---|
Metal | Usually shiny, malleable, ductile; good heat/electricity conductor | Fe, Cu, Al |
Non-metal | Usually a poor conductor; solid forms generally brittle | S, O, C |
Metalloid | Some metallic and some non-metallic properties | B, Si, Ge |
Lustre means shine. Malleable means able to form sheets. Ductile means able to form wires. Brittle means likely to break rather than bend. A conductor lets heat or electric charge pass easily.
Silicon is a semiconductor: we can control how well it carries electric charge.
Most elements are solid at room temperature. Mercury is a liquid metal. Bromine is a liquid non-metal. Hydrogen, nitrogen and oxygen are gases. Graphite is a non-metal that conducts electricity.
An element is free when it is not combined with another element, as in Au or O₂. It is combined when it is part of a compound, as oxygen is in H₂O.
Chemical symbols
Write the first letter of a symbol as a capital. Write the second letter in lowercase: H, He, Na, Cl. Co means cobalt. CO means carbon monoxide.
Reading element symbols
Explore each part · follow the explanation
Carbon. C is carbon. Its atomic number, 6, is the number of protons.
Choose a part for its explanation. Use Focus to enlarge it, or view the whole diagram to see every connection.
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Element | Latin name | Symbol |
|---|---|---|
Sodium | Natrium | Na |
Potassium | Kalium | K |
Iron | Ferrum | Fe |
Copper | Cuprum | Cu |
First 30 elements
Atomic number is the proton count, which identifies the element.
Atomic number | Element | Symbol | Atomic number | Element | Symbol |
|---|---|---|---|---|---|
1 | Hydrogen | H | 16 | Sulfur | S |
2 | Helium | He | 17 | Chlorine | Cl |
3 | Lithium | Li | 18 | Argon | Ar |
4 | Beryllium | Be | 19 | Potassium | K |
5 | Boron | B | 20 | Calcium | Ca |
6 | Carbon | C | 21 | Scandium | Sc |
7 | Nitrogen | N | 22 | Titanium | Ti |
8 | Oxygen | O | 23 | Vanadium | V |
9 | Fluorine | F | 24 | Chromium | Cr |
10 | Neon | Ne | 25 | Manganese | Mn |
11 | Sodium | Na | 26 | Iron | Fe |
12 | Magnesium | Mg | 27 | Cobalt | Co |
13 | Aluminium | Al | 28 | Nickel | Ni |
14 | Silicon | Si | 29 | Copper | Cu |
15 | Phosphorus | P | 30 | Zinc | Zn |
Compound
Definition
A compound is a pure substance formed when different elements chemically combine in a fixed proportion.
Understand it simply
Different elements join in a set ratio to make a compound. Water always has 2 hydrogen atoms for every oxygen atom.
Example: water
H₂O has 2 H atoms for every O atom. The atom ratio is 2:1. But H and O have different masses. Using H = 1 and O = 16, the mass ratio is 2:16, or 1:8. Atom ratio and mass ratio are not the same.
Essential properties
A compound has a fixed composition.
Its properties differ from those of its elements.
Physical methods cannot separate it into its elements. A suitable chemical change is needed.
Molecules, ions and formula units
Water, CO₂ and NH₃ contain separate molecules. Solid ionic compounds contain positive and negative ions in a repeating three-dimensional pattern. This pattern is a crystal lattice.
Solid NaCl does not contain separate NaCl molecules. Its formula gives a 1:1 ratio of Na⁺ to Cl⁻. MgCl₂ gives a 1:2 ratio of Mg²⁺ to Cl⁻. A formula shows the elements and their numbers or simplest ion ratio.
Common compounds
Compound | Formula |
|---|---|
Water | H₂O |
Carbon dioxide | CO₂ |
Ammonia | NH₃ |
Sodium chloride | NaCl |
Sodium hydroxide | NaOH |
Silicon dioxide | SiO₂ |
Calcium oxide | CaO |
Calcium carbonate | CaCO₃ |
Sulfuric acid | H₂SO₄ |
Sucrose | C₁₂H₂₂O₁₁ |
Sodium carbonate | Na₂CO₃ |
Washing soda | Na₂CO₃·10H₂O |
Sodium hydrogen carbonate | NaHCO₃ |
Washing soda is Na₂CO₃·10H₂O. The dot shows water present in a fixed ratio in the crystal. This is water of crystallization. Anhydrous Na₂CO₃ has none of this water.
Salts in daily life
Use | Examples or explanation |
|---|---|
Food flavouring | Sodium chloride |
Food preservation | Certain salts, such as sodium nitrite, sodium sulfite and sodium citrate, are used for suitable purposes |
Fertilizers | Ammonium sulfate and ammonium nitrate supply plant nutrients |
Traditional photography | Light-sensitive silver salts |
Plaster casts | Plaster of Paris, calcium sulfate hemihydrate, CaSO₄·½H₂O, sets after mixing with water |
Chemical industry | Sodium chloride is an important raw material |
A salt is an ionic compound of cations and anions. Plaster of Paris is CaSO₄·½H₂O: one water molecule per two CaSO₄ units, on average.
Pure substances and mixtures
Elements and compounds are pure substances. A mixture contains substances physically combined in variable proportions; its components retain their chemical identities.
Classification of matter
Explore each part · follow the explanation
Pure substances. A pure substance has a fixed composition. Elements and compounds are pure substances.
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Mixture | Composition | Examples |
|---|---|---|
Homogeneous | Uniform throughout | Salt solution, clean dry air |
Heterogeneous | Non-uniform; different regions or phases | Sand and water, oil and water, blood |
Blood has cells suspended in liquid plasma. Blood plasma is not the plasma state of matter.
How mixture composition differs
Change the model · explore the parts
What changes when you choose Heterogeneous instead of Homogeneous?
Choose what you expect, then test it below. You can explore without answering first.
Both colours represent different components. There are 30 particles in total.
Switch between Homogeneous and Heterogeneous. Compare different regions of the container.Colours distinguish components. Their distribution changes, but their total numbers remain the same.
Change the controls to see the result. Choose Explore diagram parts for a guided explanation.
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Separation methods
Method | Principle and example |
|---|---|
Filtration | Filter retains insoluble solid: sand from water |
Evaporation | Solvent changes into vapour, leaving dissolved solid: salt from solution |
Crystallization | Crystals form from a suitable solution |
Distillation | Liquid changes into vapour and its vapour condenses: water from salt solution |
A solvent is a substance that dissolves another substance. Insoluble means that a substance dissolves very little in the given solvent. Condensation is the change from vapour to liquid.
Feature | Element | Compound | Mixture |
|---|---|---|---|
Composition | One type of atom | Different elements in a fixed proportion | Substances in variable proportions |
Pure substance? | Yes | Yes | No |
Physical separation into components | Not applicable | Not possible | Possible by suitable methods |
Chemical breakdown | Cannot form simpler substances by ordinary reactions | Can form simpler substances in suitable reactions | Not required for physical separation |
Example | Copper | Pure water | Salt solution |
Looking uniform does not prove that a substance is pure. Salt solution is uniform, but it is a mixture.
Ion
Definition
An ion is an atom or group of atoms with a net electric charge.
Understand it simply
Protons are positive and electrons are negative. If their numbers do not balance, the particle has a charge.
Formation and examples
Type | Formation from a neutral atom | Example |
|---|---|---|
Cation: positive ion | Electron loss | Na → Na⁺ + e⁻ |
Anion: negative ion | Electron gain | Cl + e⁻ → Cl⁻ |
Na⁺ has 11 protons and 10 electrons. Cl⁻ has 17 protons and 18 electrons. Making these ions changes electrons, not protons. Losing a negative electron makes an atom more positive.
Making ions from neutral atoms
Explore each part · follow the explanation
Lose an electron. Na loses one electron to form Na⁺. It still has 11 protons but now has 10 electrons.
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A superscript is a small raised symbol. Mg²⁺ has charge +2. O²⁻ has charge −2. A monatomic ion is one charged atom. A polyatomic ion is a charged group of bonded atoms.
Common polyatomic ions
Name | Formula | Overall charge |
|---|---|---|
Ammonium | NH₄⁺ | +1 |
Hydroxide | OH⁻ | −1 |
Nitrate | NO₃⁻ | −1 |
Carbonate | CO₃²⁻ | −2 |
Sulfate | SO₄²⁻ | −2 |
The charge belongs to the whole polyatomic ion. It is not the charge on each atom.
Molecular ion
A molecular ion forms when a molecule gains or loses electron(s) while remaining together: O₂ + e⁻ → O₂⁻. “Polyatomic” describes composition; “molecular ion” emphasizes formation from a molecule.
Free radical
A free radical contains at least one unpaired electron. Examples: H•, Cl•, CH₃•. The dot represents an unpaired electron, not electric charge.
An unpaired electron has no partner in its orbital. An orbital describes where an electron is likely to be found. A bond can split so that each atom takes 1 electron from the shared pair. This is homolytic cleavage. Suitable light can cause Cl₂ → 2Cl•.
Ion = net charge; radical = unpaired electron. Some species, such as O₂⁻, have both. A chemical species is a particular kind of atom, molecule, ion or radical.
Valency
Valency is the combining capacity of an atom. In simple compounds, it is related to how many electrons the atom loses, gains or shares. Oxygen has valency 2 in H₂O; carbon has valency 4 in CH₄.
Elements | Common valencies used at this level |
|---|---|
H, Li, Na, K, F | 1 |
Be, Mg, Ca, Zn, O | 2 |
B, Al | 3 |
C, Si | 4 |
He, Ne, Ar | 0 in ordinary elementary examples |
N | Usually 3 in simple covalent examples |
P | 3, 5 |
S | 2, 4, 6 in classical formula-writing tables |
Cl | Commonly 1; also 3, 5, 7 in classical tables |
Fe | 2, 3 |
Cu | 1, 2 |
Some elements have different valencies in different compounds. This is variable valency. Valency has no + or − sign. Mg has valency 2; Mg²⁺ has charge 2+. Oxidation number follows separate electron-counting rules and can have a sign.
Writing ionic formulae
Balance total positive and negative charges, then use the simplest whole-number ion ratio.
Ions | Charge balance | Formula |
|---|---|---|
Mg²⁺, Cl⁻ | 1(+2) + 2(−1) = 0 | MgCl₂ |
Al³⁺, O²⁻ | 2(+3) + 3(−2) = 0 | Al₂O₃ |
Ca²⁺, OH⁻ | 1(+2) + 2(−1) = 0 | Ca(OH)₂ |
Use brackets around a polyatomic ion that repeats. Ca(OH)₂ has 1 Ca, 2 O and 2 H atoms. Use the simplest ratio: MgO, not Mg₂O₂. Leave ionic charges out of a neutral compound’s formula.
Atomic Number
Definition
Atomic number, Z, is the number of protons in an atom’s nucleus.
Understand it simply
To find the atomic number, count protons. The number of neutrons does not affect it.
Example
Every oxygen atom has 8 protons, so Z = 8. Gaining electrons to form O²⁻ does not change Z.
Particle counts
Neutral atom: electrons = protons = Z.
Cation: electrons = Z − positive charge number.
Anion: electrons = Z + negative charge magnitude.
Species | Z | Protons | Electrons | Reason |
|---|---|---|---|---|
Na | 11 | 11 | 11 | Neutral |
Na⁺ | 11 | 11 | 10 | Lost one electron |
Mg²⁺ | 12 | 12 | 10 | Lost two electrons |
Cl⁻ | 17 | 17 | 18 | Gained one electron |
O²⁻ | 8 | 8 | 10 | Gained two electrons |
Remember: Z always counts protons. It equals electron number only for a neutral atom.
Mass Number and Atomic Mass
Mass number
Mass number, A, is the total number of protons and neutrons in one nucleus. Protons and neutrons together are called nucleons.
Understand it simply
Count protons and neutrons together to find A. To find neutrons alone, subtract Z from A.
A = protons + neutrons
Z = protons
Neutrons = A − Z
Mass number counts particles, so it is a whole number without a unit. Write A at the upper left of the element symbol. Write Z at the lower left.
Atomic number and mass number
Change the model · explore the parts
Choose a heavier isotope of the same element. What must change?
Choose what you expect, then test it below. You can explore without answering first.
Start with the selected neutral atom. Compare its proton, neutron and electron counts.
Choose the isotope with the next higher mass number. Read A, Z and the three particle counts.Changing the isotope changes neutrons and mass number. Proton number and the neutral atom’s electron count stay fixed. Shell rings are a model, not literal paths.
Change the controls to see the result. Choose Explore diagram parts for a guided explanation.
View complete static diagram
Worked particle counts
Given | Protons | Neutrons | Electrons |
|---|---|---|---|
11 protons, 12 neutrons | Z = 11 | 12; A = 11 + 12 = 23 | 11 if neutral |
A = 40, Z = 20 | 20 | 40 − 20 = 20 | 20 if neutral |
²³Na⁺; Z = 11 | 11 | 23 − 11 = 12 | 11 − 1 = 10 |
Isotopes
Isotopes are atoms of the same element with different neutron numbers: same Z, different A. Chlorine-35 and chlorine-37 both have 17 protons, but 18 and 20 neutrons respectively.
Atomic mass and relative atomic mass
Quantity | Meaning | Unit |
|---|---|---|
Atomic mass | Mass of an atom | Usually u |
Unified atomic mass unit, u | One-twelfth of a carbon-12 atom’s mass | 1 u ≈ 1.66 × 10⁻²⁴ g |
Relative atomic mass, Ar | Average atomic mass divided by 1 u | None |
Carbon-12 has mass exactly 12 u. Mass number counts protons and neutrons. Atomic mass measures mass. Relative atomic mass is an average that gives more weight to the more common isotopes. Abundance tells us how common an isotope is.
Weighted-average example
For a simplified sample with 75% chlorine-35 and 25% chlorine-37:
Ar = (75/100 × 35) + (25/100 × 37)
= 26.25 + 9.25 = 35.5.
The result is nearer 35 because that isotope is more abundant.
Molecular mass and formula mass
Molecular mass = sum of atomic masses in one molecule. Formula mass = sum of atomic masses in one formula unit; used for ionic compounds, which have no separate molecules. Both are expressed in u.
Example: HNO₃
Given: H = 1 u, N = 14 u, O = 16 u.
Count: 1 H, 1 N, 3 O.
Molecular mass = 1(1) + 1(14) + 3(16)
= 1 + 14 + 48 = 63 u.
Example: Al₂(SO₄)₃
Given: Al = 27 u, S = 32 u, O = 16 u.
Count: 2 Al; 3 S; 3 × 4 = 12 O.
Formula mass = 2(27) + 3(32) + 12(16)
= 54 + 96 + 192 = 342 u.
Using Al = 26.98 u instead gives 341.96 u. Use the supplied atomic masses.
Relative molecular mass, Mr, is molecular mass divided by 1 u: its numerical value is the same, but it has no unit. H₂O: molecular mass ≈ 18 u; Mr ≈ 18.
Empirical and molecular formulae
Formula | Shows | Glucose example |
|---|---|---|
Empirical | Simplest whole-number atom ratio | CH₂O |
Molecular | Actual atom numbers per molecule | C₆H₁₂O₆ |
For glucose, divide all three numbers in 6:12:6 by 6. The simplest ratio is 1:2:1. Different compounds can have the same simplest ratio.
Compound | Molecular formula | Empirical formula |
|---|---|---|
Carbon dioxide | CO₂ | CO₂ |
Hydrogen peroxide | H₂O₂ | HO |
Benzene | C₆H₆ | CH |
Glucose | C₆H₁₂O₆ | CH₂O |
Acetic acid | C₂H₄O₂ | CH₂O |
CH₃COOH shows how some atoms are grouped in acetic acid. Counting all its atoms gives the molecular formula C₂H₄O₂.
Finding a molecular formula
Molecular formula = (Empirical formula)ₙ
n = molecular mass / empirical formula mass.
Here n is a positive whole-number multiplier; in mole calculations, n instead denotes amount of substance.
Example: Empirical formula CH₂O; molecular mass 180 u.
Empirical formula mass = 12 + 2(1) + 16 = 30 u.
n = 180/30 = 6.
Multiply every subscript by 6: C₁H₂O₁ → C₆H₁₂O₆.
Mole
Definition
One mole is the amount of substance containing exactly 6.02214076 × 10²³ specified entities. An entity is the atom, molecule, ion or formula unit being counted.
Understand it simply
A dozen counts 12 items. A mole counts a much larger fixed number. Always name what you are counting.
Avogadro constant: NA = 6.02214076 × 10²³ mol⁻¹ exactly. The unit mol⁻¹ means per mole. Calculations here use the book’s rounded value 6.02 × 10²³ mol⁻¹.
Same count, different masses
Amount | Specified entities | Approximate mass |
|---|---|---|
1 mol O atoms | NA oxygen atoms | 16 g |
1 mol O₂ molecules | NA molecules; 2NA O atoms | 32 g |
1 mol H₂O molecules | NA water molecules | 18 g |
1 mol NaCl | NA formula units | 58.5 g |
10²³ means 1 followed by 23 zeros. Scientific notation helps us write very large or small numbers. It uses a number from 1 to less than 10, multiplied by a power of 10.
Molar mass and textbook terms
Molar mass, M, is mass per mole, usually in g mol⁻¹. One H₂O molecule has mass about 18 u; one mole has mass about 18 g, so M ≈ 18 g mol⁻¹.
Term | Meaning | Example |
|---|---|---|
Gram atomic mass | Mass of one mole of atoms | 16 g of O atoms |
Gram molecular mass | Mass of one mole of molecules | 32 g of O₂ molecules |
Gram formula mass | Mass of one mole of formula units | 58.5 g of NaCl |
Core relationships
n = m/M; m = nM
N = nNA; n = N/NA
Therefore N = (m/M)NA.
n is moles; m is mass in grams; M is molar mass in g mol⁻¹; N counts the named particles. To find moles, divide the sample’s mass by the mass of 1 mole.
Moles connect measurable quantities
Explore each part · follow the explanation
Mass ↔ moles. Divide mass by molar mass to find moles: n = m/M. Multiply moles by molar mass to find mass: m = nM.
Choose a part for its explanation. Use Focus to enlarge it, or view the whole diagram to see every connection.
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1. Moles in 40 g Na
Given: m = 40 g; M = 23 g mol⁻¹. Find n.
n = m/M = 40 g / (23 g mol⁻¹)
= 1.739… mol ≈ 1.74 mol Na.
Grams cancel, leaving mol.
2. Mass of 4 mol CO₂
Given: n = 4 mol. Find m.
M = 12 + 2(16) = 44 g mol⁻¹.
m = nM = 4 mol × 44 g mol⁻¹ = 176 g CO₂.
3. Atoms in 9.2 g Ca
Given: m = 9.2 g; M = 40 g mol⁻¹. Find N.
First convert mass to moles: n = 9.2/40 = 0.23 mol.
Then count atoms: N = nNA = 0.23 × 6.02 × 10²³
= 1.3846 × 10²³ ≈ 1.38 × 10²³ Ca atoms.
4. Moles and molecules in 8 g glucose
Given: m = 8 g; C₆H₁₂O₆. Find n and N.
M = 6(12) + 12(1) + 6(16)
= 72 + 12 + 96 = 180 g mol⁻¹.
n = m/M = 8/180 = 0.04444… mol.
N = (8/180) × 6.02 × 10²³
≈ 2.68 × 10²² molecules.
Keep the unrounded fraction until the final answer.
5. Moles in 8.5 g silver
Assume the stated mass is silver. Using the supplied M = 107 g mol⁻¹:
n = m/M = 8.5 g / (107 g mol⁻¹)
≈ 0.0794 mol Ag.
If M = 108 g mol⁻¹ is supplied instead, n ≈ 0.0787 mol.
6. Moles, molecules and atoms in 10 g H₂SO₄
Given: m = 10 g. Find n, molecules and total atoms.
M = 2(1) + 32 + 4(16) = 98 g mol⁻¹.
n = m/M = 10/98 ≈ 0.102 mol.
Molecules = (10/98) × 6.02 × 10²³ ≈ 6.14 × 10²².
Each molecule has 2 + 1 + 4 = 7 atoms.
Total atoms = 7 × (10/98) × 6.02 × 10²³ ≈ 4.30 × 10²³.
For oxygen atoms only, multiply the molecule count by 4.
Formula units and ions
1 mol NaCl contains 1 mol Na⁺ and 1 mol Cl⁻. That is 2 mol ions altogether. It is still only 1 mol NaCl.
Mole–volume calculations
Here STP means 0 °C and 1 atm. At these conditions, 1 mole of an ideal gas occupies about 22.4 L. Some sources use 1 bar for STP, so always check the conditions. An ideal gas is a simplified model.
V = n × 22.4 L mol⁻¹
n = V / (22.4 L mol⁻¹)
1 L = 1 dm³. Do not apply this molar volume to liquids or solids.
Additional practice: 0.5 mol O₂
Given: n = 0.5 mol at 0°C and 1 atm. Find V.
V = n × 22.4 L mol⁻¹
= 0.5 mol × 22.4 L mol⁻¹ = 11.2 L.
7. CO₂ from 0.450 mol CO
Given: excess O₂; 0°C and 1 atm. Find CO₂ volume. Excess means more reactant than required.
Equation: 2CO + O₂ → 2CO₂.
Mole ratio CO : CO₂ = 2 : 2 = 1 : 1.
So 0.450 mol CO forms 0.450 mol CO₂.
V = 0.450 × 22.4 = 10.08 L ≈ 10.1 L.
Coefficients give mole ratios; they do not give direct mass ratios.
Chemical Reaction and Equation
Chemical reaction
A chemical reaction forms new substances through rearrangement of atoms and changes in bonding. Reactants are starting substances; products are substances formed.
Understand it simply
In a chemical reaction, atoms join in new ways. The starting substances change into new substances.
Chemical equation
A chemical equation represents a reaction using symbols and formulae: reactants → products.
Example: 2H₂(g) + O₂(g) → 2H₂O(l).
Two hydrogen molecules react with one oxygen molecule to form two water molecules. Mole ratio = 2 : 1 : 2.
Reading a chemical equation
Explore each part · follow the explanation
Reactants and product. Hydrogen and oxygen are reactants, written on the left. Water is the product, written on the right.
Choose a part for its explanation. Use Focus to enlarge it, or view the whole diagram to see every connection.
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Symbols
Symbol | Meaning |
|---|---|
+ | Separates substances on the same side; read as “reacts with” on the reactant side |
→ | Produces |
⇌ | Forward and reverse reactions are possible |
(s) | Solid |
(l) | Liquid |
(g) | Gas |
(aq) | Aqueous: dissolved in water |
Δ above the arrow | Heating |
Aqueous means dissolved in water. A reversible reaction can go in both directions. A catalyst changes reaction speed without being used up overall. Show it above or below the arrow.
Coefficient versus subscript
A coefficient multiplies the whole formula. So 2H₂O has 4 H and 2 O atoms. A subscript is part of the formula. H₂O₂ is different from H₂O. When balancing, change coefficients only.
Why balance?
The law of conservation of mass states that the total mass remains unchanged during a chemical reaction in a closed system. A closed system does not exchange matter with its surroundings.
Therefore, each element must have the same number of atoms on both sides of the equation.
Inspection method
1. Write the correct formulas.
2. Count each kind of atom on both sides.
3. Change coefficients until the counts match.
4. Use the smallest whole-number ratio.
5. Check every element again.
Worked example: potassium chlorate
Heating KClO₃ produces KCl and O₂.
1. Skeleton equation: KClO₃ → KCl + O₂.
2. K and Cl match; O counts are 3 and 2.
3. Make O counts 6: 2KClO₃ → KCl + 3O₂.
4. Balance K and Cl: 2KClO₃ → 2KCl + 3O₂.
5. Check: K = 2, Cl = 2, O = 6 on each side.
Final: 2KClO₃(s) → 2KCl(s) + 3O₂(g), with Δ above the arrow to indicate heating. Use the actual substance formula—oxygen gas is O₂, not O.
Branches of Chemistry
Understand it simply
Each branch studies part of chemistry. The branches often work together.
Branch | Main focus | Example |
|---|---|---|
Physical | Physical principles governing chemical behaviour: energy, gases and reaction rates | Effect of temperature on reaction speed |
Organic | Structures, properties, preparation and reactions of organic carbon compounds | Fuels, alcohols, plastics |
Inorganic | Elements and inorganic compounds | Metals, salts, minerals, ceramics |
Biochemistry | Substances and reactions in living organisms | Proteins, fats, digestion |
Industrial | Large-scale chemical manufacturing | Fertilizers, cement, medicines |
Nuclear | Nuclear properties, radioactivity and transformations | Cancer treatment; nuclear power |
Environmental | Chemical processes and substances in the environment | Pollutants in air and water |
Analytical | Identifying substances and measuring their amounts | Measuring salt in a sample |
Medicinal | Design, preparation and improvement of drugs | Developing an effective medicine |
Quantum | Applying quantum mechanics to chemical systems | Electron states and bonding |
Green | Designing products/processes that reduce or eliminate hazardous substances | Safer solvents, less waste and energy use |
Essential terms and distinctions
Hydrocarbon: contains only carbon and hydrogen. Derivative: a related compound formed by replacing atom(s) or groups. CO, CO₂, carbonates, hydrogen carbonates and many cyanides are usually studied in inorganic chemistry.
Mineral: naturally occurring solid with characteristic composition and structure. Metallurgy: extracting and processing metals. Ore: material from which a useful component can be extracted economically.
Biomolecules: molecules associated with living organisms. Metabolism: all chemical reactions in an organism. Radioactivity: spontaneous change of unstable nuclei with emission of radiation.
Qualitative analysis asks: “Which substances are present?” Quantitative analysis asks: “How much is present?” Chromatography separates substances because they travel at different rates through a material. Electrophoresis separates charged particles using an electric field. Spectroscopy studies how matter interacts with radiation, such as light.
Quantum mechanics explains matter and energy on very small scales. Hazardous means able to cause harm. Green chemistry aims to prevent waste and hazards. Environmental chemistry studies chemicals in the environment and their effects.
Historical Background
Understand it simply
Early thinkers used reasoning to explain matter. Modern chemistry grew through experiments and measurements. A hypothesis is an explanation we can test. A scientific theory is an explanation strongly supported by evidence.
Early ideas and practical chemistry
Scientist or thinker | Contribution |
|---|---|
Democritus | Proposed that matter consists of tiny indivisible particles called atoms |
Plato | Developed philosophical ideas about elements and geometric forms |
Aristotle | Supported the four-element model: earth, water, air and fire |
Jabir ibn Hayyan | Associated with early experimental methods, chemical preparations and metal extraction |
Al-Razi | Contributed to practical chemistry, descriptions of substances and medicine |
Al-Biruni | Investigated densities of different substances |
Ibn Sina | Made major contributions to medicine and related natural philosophy |
Gases and modern chemical ideas
Scientist | Contribution |
|---|---|
Robert Boyle | Studied the pressure–volume relation of gases and promoted experimental investigation |
Joseph Black | Studied carbon dioxide, historically called “fixed air” |
Joseph Priestley | Independently prepared oxygen and investigated several gases |
Carl Wilhelm Scheele | Independently prepared oxygen and prepared chlorine |
Henry Cavendish | Identified hydrogen as a distinct gas |
Antoine Lavoisier | Explained combustion using oxygen and helped establish quantitative chemistry |
John Dalton | Proposed a modern atomic theory of matter |
Jacques Charles | Studied how gas volume changes with temperature |
Joseph Louis Gay-Lussac | Studied simple whole-number ratios of reacting gas volumes |
Amedeo Avogadro | Proposed that equal gas volumes at the same temperature and pressure contain equal numbers of molecules |
Notation, periodic arrangement and electricity
Scientist | Contribution |
|---|---|
Dulong and Petit | Established an approximate relation for the molar heat capacities of many solid elements |
J. J. Berzelius | Developed modern chemical-symbol notation |
Dmitri Mendeleev | Developed a periodic arrangement of elements |
Svante Arrhenius | Proposed electrolyte dissociation and an acid–base theory |
Michael Faraday | Established laws of electrolysis and contributed to the study of electromagnetism |
Atomic structure and quantum ideas
Scientist | Contribution |
|---|---|
J. J. Thomson | Discovered the electron |
Ernest Rutherford | Established the nuclear model; distinguished alpha and beta radiation and investigated radioactive change |
Niels Bohr | Proposed quantized electron energy levels for hydrogen |
Louis de Broglie | Proposed the wave nature of matter |
Erwin Schrödinger | Developed a wave-mechanical description of atoms |
S. N. Bose and Albert Einstein | Developed theory underlying Bose–Einstein condensation |
Eric Cornell and Carl Wieman, with their team | Produced a dilute-gas Bose–Einstein condensate |
Democritus suggested indivisible particles. Much later, Dalton developed a scientific atomic theory. These were different stages in our understanding of atoms.
Combustion = burning, usually with oxygen. Heat capacity = energy needed for a specified temperature rise. Periodic = recurring in a pattern. An electrolyte supplies mobile ions in solution or when molten; dissociation separates particles such as ions; electrolysis uses electricity to drive chemical change.
Quantized energy allows only certain energy values. Bose–Einstein condensation happens at extremely low temperatures. It is different from plasma, which contains mobile charged particles.
States of Matter
Understand it simply
A state of matter is a physical form, such as solid, liquid or gas. It depends on how particles are arranged, how they move and how they attract one another.
Property | Solid | Liquid | Gas |
|---|---|---|---|
Shape | Definite | Container’s shape | Fills container |
Volume | Definite | Definite | Not definite |
Particles | Close; vibrate about fixed positions | Close; move past one another | Far apart; move freely |
Compressibility | Very low | Very low | High |
Water example | Ice | Liquid water | Water vapour |
Compressibility tells us how easily volume decreases under pressure. Gases are easy to compress because their particles have large spaces between them.
Plasma
Plasma has moving electrons and positive ions. Adding enough energy can remove electrons from gas atoms. This is ionization. Stars and lightning contain plasma.
Particle models of matter
Change the model · explore the parts
When a solid becomes a liquid, what mainly changes in this particle model?
Choose what you expect, then test it below. You can explore without answering first.
The model contains 30 particles. Start with Solid.
Press Play movement, then choose Liquid and Gas. Compare spacing and movement.Solid particles vibrate close to fixed positions.
Change the controls to see the result. Choose Explore diagram parts for a guided explanation.
View complete static diagram
Changes of state
Melting: solid → liquid. Freezing: liquid → solid.
Vaporization: liquid → gas. Condensation: gas → liquid.
Heating usually makes particles move faster. During melting or boiling, energy can change the arrangement without raising temperature. Ice, liquid water and water vapour are all H₂O. Changing state does not make a new substance.
Exercise: Short Questions
1. Differentiate between physical and analytical chemistry.
Physical chemistry | Analytical chemistry |
|---|---|
Studies physical principles governing chemical behaviour | Identifies substances and measures their amounts |
Includes energy changes, gas behaviour and reaction rates | Includes qualitative and quantitative analysis |
Example: Effect of temperature on reaction speed | Example: Amount of salt in drinking water |
2. Write the classification of molecules.
Molecules can be classified by atomicity and by the type of atoms present.
By atomicity: Diatomic, triatomic and other polyatomic molecules.
By composition: Homoatomic and heteroatomic molecules.
H₂O is triatomic because it has three atoms and heteroatomic because it has two different elements.
Helium, neon and argon are monatomic species: they exist as individual atoms.
3(a). Differentiate between an atom and an ion.
Atom | Ion |
|---|---|
Electrically neutral | Has a net positive or negative charge |
Proton and electron numbers are equal | Positive and negative charges do not balance |
Example: Na | Example: Na⁺ |
When Na loses one electron it becomes Na⁺. The proton count remains unchanged.
3(b). Differentiate between a molecule and a molecular ion.
A molecule is electrically neutral. A molecular ion is a charged species formed when a molecule gains or loses electron(s) while its atoms remain together.
Example: O₂ is a molecule; O₂⁻ is a molecular ion.
3(c). Differentiate between a compound and a mixture.
Compound | Mixture |
|---|---|
Elements are chemically combined | Substances are physically combined |
Has a fixed composition | Composition can vary |
Has properties different from those of the elements that form it | Components retain their chemical identities |
Cannot be separated into elements by physical methods | Can be separated by suitable physical methods |
Example: Pure H₂O | Example: Salt solution |
4. Define gram atomic mass, gram molecular mass and gram formula mass.
Gram atomic mass: Mass of one mole of atoms. Example: About 12 g of carbon atoms.
Gram molecular mass: Mass of one mole of molecules. Example: About 18 g of H₂O molecules.
Gram formula mass: Mass of one mole of formula units. Example: About 58.5 g of NaCl.
These are textbook terms. Molar mass expresses the corresponding mass per mole, in g mol⁻¹.
5. Write chemical, empirical and molecular formulae.
A chemical formula is the general representation of composition. A molecular formula gives actual atoms per molecule; an empirical formula gives their simplest ratio.
Compound | Molecular formula | Empirical formula |
|---|---|---|
Sulfuric acid | H₂SO₄ | H₂SO₄ |
Carbon dioxide | CO₂ | CO₂ |
Glucose | C₆H₁₂O₆ | CH₂O |
Benzene | C₆H₆ | CH |
The subscripts of H₂SO₄ and CO₂ have no common factor greater than 1, so their empirical and molecular formulae are the same.
6. What is a free radical?
A free radical is an atom or group of atoms containing at least one unpaired electron.
Examples: H•, Cl• and CH₃•.
The dot represents an unpaired electron; it does not represent an electric charge.
7. Relate empirical and molecular formulae with an example.
Molecular formula = (Empirical formula)ₙ, where n is a positive whole-number multiplier.
For benzene, C₆H₆ reduces from 6 : 6 to 1 : 1, so its empirical formula is CH.
Its molecular formula is (CH)₆ = C₆H₆. Every subscript is multiplied by 6.
8. Why are hydrogen and oxygen elements, but water a compound?
H₂ contains only hydrogen atoms. O₂ contains only oxygen atoms. Each is therefore an element.
H₂O contains two different elements chemically bonded in a fixed ratio. It is therefore a compound.
Exercise: Detailed Questions
1. Explain chemical species, ions, molecular ions and free radicals.
A chemical species is a particular kind of atom, molecule, ion or radical.
An ion carries a net electric charge. It may be one atom or a group of bonded atoms.
A cation has positive charge and forms by electron loss: Na → Na⁺ + e⁻.
An anion has negative charge and forms by electron gain: Cl + e⁻ → Cl⁻.
A molecular ion forms when a molecule gains or loses electron(s) without fragmenting. For example: O₂ + e⁻ → O₂⁻.
A free radical contains at least one unpaired electron, represented by a dot.
Suitable light causes chlorine to undergo homolytic cleavage: Cl₂ → 2Cl•.
Each chlorine takes one electron from the shared pair. Charge and an unpaired electron are different properties; a species may have both.
2. Explain applications of chemistry in daily life.
Chemistry helps us understand substances and their changes in homes, living organisms and industry.
Food: Cooking changes food; preservation delays spoilage; digestion breaks food into absorbable substances.
Health: Chemical research helps develop medicines. Biochemistry helps explain normal body processes and disease.
Agriculture: Fertilizers supply nutrients needed by crops.
Cleaning: Soaps and detergents help remove dirt and grease.
Water: Treatment removes impurities; suitable disinfection kills many harmful microorganisms.
Materials: Chemical industries produce glass, cement, plastics, paints and synthetic fibres.
3. Explain empirical and molecular formulae.
An empirical formula gives the simplest whole-number atom ratio of the elements in a compound.
A molecular formula gives the actual number of atoms of each element in one molecule.
For glucose, C₆H₁₂O₆ gives the atom ratio 6 : 12 : 6.
Dividing each number by 6 gives 1 : 2 : 1, so its empirical formula is CH₂O.
Molecular formula = (Empirical formula)ₙ.
The multiplier n is found by dividing molecular mass by empirical formula mass, with both in the same units.
For glucose: empirical formula mass = 30 u and molecular mass = 180 u.
n = 180 / 30 = 6; therefore, molecular formula = C₆H₁₂O₆.
For CO₂, n = 1. Thus, empirical and molecular formulae may be the same.
4. Explain the steps of balancing a chemical equation.
A balanced equation has equal atom counts for every element on both sides. This is consistent with conservation of mass.
Step 1: Write correct formulae: KClO₃ → KCl + O₂.
Step 2: Count atoms. K and Cl are equal, but O is 3 on the left and 2 on the right.
Step 3: Make oxygen counts 6: 2KClO₃ → KCl + 3O₂.
Step 4: Balance K and Cl: 2KClO₃ → 2KCl + 3O₂.
Step 5: Verify: both sides contain 2 K, 2 Cl and 6 O atoms.
Only coefficients are changed. Subscripts must remain those of the correct substances.
5. Name the branches of chemistry and discuss any five.
The branches listed in the textbook are physical, organic, inorganic, biochemistry, industrial, nuclear, environmental, analytical, medicinal, quantum and green chemistry.
Physical chemistry studies physical principles of chemical behaviour, including energy changes and reaction rates.
Organic chemistry studies organic carbon compounds, including hydrocarbons and their derivatives.
Inorganic chemistry studies elements and inorganic compounds such as metals, salts and minerals.
Biochemistry studies chemical substances and reactions in living organisms, including proteins and metabolism.
Analytical chemistry identifies substances and determines their amounts. It includes qualitative and quantitative analysis.
Exercise: Solved Numericals
Use the rounded atomic masses supplied in each question. For this exercise: H = 1, C = 12, N = 14, O = 16, Na = 23, Mg = 24, Al = 27, S = 32, Cl = 35.5, K = 39 and Ca = 40, in u.
For particle calculations use NA ≈ 6.02 × 10²³ mol⁻¹.
1(a). Balance NH₃ + O₂ → NO + H₂O.
Step 1: Inspect nitrogen and hydrogen.
NH₃ has three H atoms; H₂O has two. Choosing an even number of NH₃ molecules avoids a fractional H₂O coefficient.
Start with 4NH₃. This contains 4 N and 12 H atoms.
Step 2: Balance N.
Put 4 before NO.
Step 3: Balance H.
Twelve H atoms require 6H₂O.
Step 4: Balance O.
4NO contains 4 O atoms and 6H₂O contains 6 O atoms.
Total O atoms in products = 10, supplied by 5O₂.
Answer: 4NH₃ + 5O₂ → 4NO + 6H₂O
Check: N = 4, H = 12, O = 10 on each side.
1(b). Balance KNO₃ → KNO₂ + O₂.
Step 1: Put 2 before KNO₃ and KNO₂. K and N are then balanced at 2 each.
Step 2: Left O = 2 × 3 = 6. Oxygen in 2KNO₂ = 2 × 2 = 4.
Step 3: The remaining 2 O atoms form one O₂ molecule.
Answer: 2KNO₃ → 2KNO₂ + O₂
Check: K = 2, N = 2, O = 6 on each side.
1(c). Balance Ca + H₂O → Ca(OH)₂ + H₂.
Step 1: Ca is already balanced at one atom.
Step 2: Ca(OH)₂ contains two O atoms, so put 2 before H₂O.
Step 3: The left side now has four H atoms.
On the right, Ca(OH)₂ contains two H atoms and H₂ contains two more. Total H = 4.
Answer: Ca + 2H₂O → Ca(OH)₂ + H₂
Check: Ca = 1, O = 2, H = 4 on each side.
1(d). Balance NaHCO₃ → Na₂CO₃ + H₂O + CO₂.
Step 1: Na₂CO₃ contains two Na atoms, so put 2 before NaHCO₃.
Step 2: Count remaining atoms on the left: H = 2, C = 2, O = 6.
Step 3: On the right: H = 2; C = 1 + 1 = 2; O = 3 + 1 + 2 = 6.
Answer: 2NaHCO₃ → Na₂CO₃ + H₂O + CO₂
Every element is balanced.
1(e). Balance CO + O₂ → CO₂.
Step 1: Put 2 before CO₂ to make four O atoms on the right.
Step 2: Put 2 before CO to balance two C atoms.
Step 3: Oxygen on the left = 2 from 2CO + 2 from O₂ = 4.
Answer: 2CO + O₂ → 2CO₂
Check: C = 2 and O = 4 on each side.
2(a). Calculate the formula mass of Al₂O₃.
Given: Al = 27 u; O = 16 u.
Find: Formula mass.
Step 1: Count Al = 2 and O = 3.
Step 2: Multiply: Al contribution = 2 × 27 = 54 u; O contribution = 3 × 16 = 48 u.
Step 3: Add: 54 + 48.
Answer: 102 u.
2(b). Calculate the formula mass of MgCl₂.
Given: Mg = 24 u; Cl = 35.5 u.
Step 1: Count Mg = 1 and Cl = 2.
Step 2: Formula mass = 1(24) + 2(35.5).
Step 3: 24 + 71 = 95.
Answer: 95 u.
2(c). Calculate the formula mass of NaCl.
Given: Na = 23 u; Cl = 35.5 u.
Step 1: NaCl contains one Na and one Cl per formula unit.
Step 2: Add their masses: 23 + 35.5.
Answer: 58.5 u.
2(d). Calculate the formula mass of KNO₃.
Given: K = 39 u; N = 14 u; O = 16 u.
Step 1: Count K = 1, N = 1, O = 3.
Step 2: Formula mass = 39 + 14 + 3(16).
Step 3: 39 + 14 + 48 = 101.
Answer: 101 u.
3(a). Calculate the molecular mass of C₂H₅OH.
Given: C = 12 u; H = 1 u; O = 16 u.
Step 1: Count C = 2, H = 5 + 1 = 6 and O = 1.
The H in OH must also be counted.
Step 2: Molecular mass = 2(12) + 6(1) + 16.
Step 3: 24 + 6 + 16 = 46.
Answer: 46 u.
3(b). Calculate the molecular mass of H₂O.
Step 1: Count H = 2 and O = 1.
Step 2: Molecular mass = 2(1) + 16 = 18.
Answer: 18 u.
3(c). Calculate the molecular mass of NH₃.
Step 1: Count N = 1 and H = 3.
Step 2: Molecular mass = 14 + 3(1) = 17.
Answer: 17 u.
3(d). Calculate the molecular mass of CO₂.
Step 1: Count C = 1 and O = 2.
Step 2: Molecular mass = 12 + 2(16) = 44.
Answer: 44 u.
4. How many moles are present in 40 g H₂SO₄?
Given: m = 40 g.
Find: Amount n, in mol.
Step 1: Calculate molar mass.
M = 2(1) + 32 + 4(16)
= 2 + 32 + 64
= 98 g mol⁻¹.
Step 2: Choose the relationship.
n = m/M because a mass must be converted to moles.
Step 3: Substitute with units.
n = 40 g / (98 g mol⁻¹).
Step 4: Calculate.
n = 0.408163… mol.
Answer: Approximately 0.408 mol H₂SO₄.
5(a). Find moles and molecules in 16 g H₂CO₃.
Given: m = 16 g; formula = H₂CO₃.
Find: n and number of molecules, N.
Step 1: Molar mass.
M = 2(1) + 12 + 3(16)
= 2 + 12 + 48
= 62 g mol⁻¹.
Step 2: Convert mass to moles.
n = m/M = 16/62
= 0.258064… mol.
Step 3: Convert moles to molecules.
N = nNA
= (16/62) × 6.02 × 10²³
= 1.5535… × 10²³.
Answers: n ≈ 0.258 mol; N ≈ 1.55 × 10²³ molecules.
The unrounded fraction 16/62 is used in the second calculation to avoid early-rounding error.
5(b). Find moles and molecules in 20 g C₆H₁₂O₆.
Given: m = 20 g; formula = C₆H₁₂O₆.
Find: n and N.
Step 1: Molar mass.
M = 6(12) + 12(1) + 6(16)
= 72 + 12 + 96
= 180 g mol⁻¹.
Step 2: Moles.
n = m/M = 20/180
= 0.111111… mol.
Step 3: Molecules.
N = nNA
= (20/180) × 6.02 × 10²³
= 6.6888… × 10²².
Answers: n ≈ 0.111 mol; N ≈ 6.69 × 10²² molecules.
Test Yourself: Answers
Identify chemistry in your home.
Cooking food, washing with soap, taking medicines, burning fuel and preserving food involve chemistry.
For example, burning fuel is a chemical change, while boiling water is a physical change.
Relate living things to chemistry.
Digestion, respiration and growth depend on chemical reactions.
Respiration includes the cellular processes that release usable energy from food.
Which branch studies the identity and amount of substances?
Analytical chemistry. Qualitative analysis identifies substances; quantitative analysis measures their amounts.
What can a deficiency of biomolecules cause?
A deficiency means an insufficient amount.
Insufficient essential nutrients or required biomolecules can disturb normal body functions and cause disease. The effects depend on which substance is lacking.
Give examples of green chemistry.
Using safer solvents, reducing waste, choosing catalysts and designing energy-efficient processes.
Differentiate medicinal chemistry and biochemistry.
Medicinal chemistry focuses on drug design and development. Biochemistry studies chemical substances and reactions in living organisms.
Differentiate matter and a pure substance.
Matter is anything with mass and volume. It includes both pure substances and mixtures.
A pure substance is matter with fixed chemical composition and characteristic properties.
Name the elements in these compounds.
Compound | Formula | Elements |
|---|---|---|
Washing soda | Na₂CO₃·10H₂O | Sodium, carbon, oxygen, hydrogen |
Sucrose | C₁₂H₂₂O₁₁ | Carbon, hydrogen, oxygen |
Silicon dioxide | SiO₂ | Silicon, oxygen |
Sodium hydroxide | NaOH | Sodium, oxygen, hydrogen |
Classify the materials.
Material | Classification | Reason |
|---|---|---|
Pure sodium chloride | Compound | Na and Cl chemically combined in a fixed ratio |
Ice cream | Mixture | Contains several substances |
Blood | Mixture | Contains cells and other components in plasma |
Silicon | Element | One type of atom |
Coca-Cola | Mixture | Contains water and other ingredients |
Tin | Element | One type of atom |
Zinc | Element | One type of atom |
Pure water | Compound | H and O chemically combined in a fixed ratio |
Sulfur | Element | One type of atom |
Differentiate empirical and molecular formulae.
The empirical formula shows the simplest atom ratio. The molecular formula shows actual atom numbers in a molecule.
For H₂O₂, the ratio 2 : 2 reduces to 1 : 1, giving empirical formula HO.
Why distinguish molecular mass and formula mass?
A molecule is a separate bonded group of atoms. An ionic crystal is a repeating ion lattice.
Molecular mass refers to one molecule; formula mass refers to the composition of one formula unit. Both are obtained by adding the appropriate atomic masses.
Classify the chemical species.
Species | Classification |
|---|---|
O₂, N₂, Cl₂, H₂, H₂O | Neutral molecules |
H⁺ and Na⁺ | Cations |
CO₃²⁻ | Polyatomic anion |
CH₃• | Free radical |
Br without a written charge or dot | Neutral bromine atom |
A neutral bromine atom itself has an unpaired electron and can be described as a radical when electronic structure is considered. The printed symbol should be read carefully; Br• explicitly indicates the radical.
Justify the classification of molecules.
Use the total number of atoms and whether they belong to the same or different elements.
H₂O contains three atoms from two elements: triatomic and heteroatomic.
O₃ contains three atoms from one element: triatomic and homoatomic.
Balance the potassium chlorate equation using coefficient 4.
Given: 4KClO₃ → 4KCl + O₂.
Left O = 4 × 3 = 12. Each O₂ contains two O atoms, so 12/2 = 6 molecules are required.
4KClO₃ → 4KCl + 6O₂
Divide every coefficient by 2 to get the simplest form:
2KClO₃ → 2KCl + 3O₂.
Balance CaCO₃ + HCl → CaCl₂ + H₂O + CO₂.
CaCl₂ contains two Cl atoms. Put 2 before HCl.
CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂
Check: Ca = 1, C = 1, O = 3, H = 2 and Cl = 2 on each side.
Relate the mole to Avogadro’s constant.
N = nNA.
For n = 1 mol:
N = 1 mol × 6.02 × 10²³ mol⁻¹
= 6.02 × 10²³ specified entities, using the textbook’s rounded value.
The particle count equals the amount in moles multiplied by the number of particles per mole.
Calculate moles in 30 g H₃PO₄.
Given: m = 30 g. Use H = 1, P = 31 and O = 16.
Find: n.
Step 1: Molar mass.
M = 3(1) + 31 + 4(16)
= 3 + 31 + 64
= 98 g mol⁻¹.
Step 2: Formula.
n = m/M.
Step 3: Substitute.
n = 30/98 = 0.306122… mol.
Answer: Approximately 0.306 mol H₃PO₄.
Quick Revision
Formula sheet
Task | Relationship |
|---|---|
Protons | Z |
Neutrons | A − Z |
Neutral atom electrons | Z |
Moles from mass | n = m/M |
Mass from moles | m = nM |
Specified particles | N = nNA |
Moles from particles | n = N/NA |
Gas volume at 0°C, 1 atm | V = n × 22.4 L mol⁻¹ |
Molecular-formula multiplier | Molecular mass / empirical formula mass |