9th Class Chemistry
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Class 9 · Sindh ChemistryFree NotesRead Online

ARMCQs DIGITAL STUDY NOTES

Chapter 1: Fundamentals of Chemistry

Chemistry with Sir Aamir Rajper

Clear concepts · Chapter-wise reading · Designed for focused revision

Definition of Chemistry

Definition

Chemistry is the branch of science that studies the composition, structure, properties and changes of matter.

Understand it simply

Chemistry helps us answer three questions: What is a substance made of? What is it like? How can it change?

Understand the terms

Term

Meaning

Example

Matter

Anything with mass that occupies space

Air, water, iron

Composition

What a material contains and in what proportion

H₂O contains H and O in a 2 : 1 atom ratio

Structure

How particles are joined and arranged

One O atom bonded to two H atoms in water

Property

A characteristic of a substance

Colour, density, ability to burn

Mass describes how much matter an object contains; volume is the space it occupies. Density = mass/volume. A chemical bond is an attraction holding atoms or ions together.

Properties and changes

Physical

Chemical

A physical property is observed without forming a new substance: colour or melting point

A chemical property describes the ability to react: iron’s ability to rust

A physical change retains chemical identity: ice → water

A chemical change forms new substances: iron → rust

Melting point is the temperature at which a solid becomes liquid at a given pressure. To identify a chemical change, ask: “Has a new substance formed?” Being easy or hard to reverse does not decide the answer.

Importance in daily life

Area

Application

Food

Cooking; digestion—breaking food into absorbable substances; preservation—delaying spoilage

Health

Developing and preparing medicines

Agriculture

Fertilizers supply nutrients needed for plant growth

Cleaning

Soaps and detergents remove dirt and grease

Water

Treatment removes impurities and harmful microorganisms (microscopic organisms)

Industry

Manufacture of glass, cement, plastics, fibres and ceramics

Scientists observe, suggest explanations and test them. The word science comes from the Latin scientia, meaning knowledge.

Atom

Definition

An atom is the smallest unit of an element that retains its chemical identity.

Understand it simply

Every element has its own kind of atom. The number of protons tells us which element it is.

Example

One copper atom is still copper. Copper atoms are identified by their proton number. An electron on its own is not a smaller copper atom.

Structure

Subatomic means smaller than an atom. The nucleus is the tiny centre. It contains protons and usually neutrons. Electrons are outside the nucleus.

Particle

Relative charge

Location

Approximate relative mass

Proton, p⁺

+1

Nucleus

1

Neutron, n

0

Nucleus

1

Electron, e⁻

−1

Outside nucleus

1/1836

INTERACTIVE MODEL

Inside a carbon-12 atom

Change the model · explore the parts

1 · PREDICT

Choose a heavier isotope of the same element. What must change?

Choose what you expect, then test it below. You can explore without answering first.

2 · TRY IT

Start with the selected neutral atom. Compare its proton, neutron and electron counts.

Choose the isotope with the next higher mass number. Read A, Z and the three particle counts.
CC126A = 12; Z = 6Neutral: charge 0Shells: 2, 4
Protons6
Neutrons6
Electrons6

Changing the isotope changes neutrons and mass number. Proton number and the neutral atom’s electron count stay fixed. Shell rings are a model, not literal paths.

Change a control and watch what changes—and what stays the same.
3 · EXPLAIN

Change the controls to see the result. Choose Explore diagram parts for a guided explanation.

View complete static diagram
Carbon-12: 6 protons, 6 neutrons and 6 electrons. Shell circles are a simplified model, not literal electron paths.
Carbon-12: 6 protons, 6 neutrons and 6 electrons. Shell circles are a simplified model, not literal electron paths.
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Carbon-12: 6 protons, 6 neutrons and 6 electrons. Shell circles are a simplified model, not literal electron paths.

Key points

Every oxygen atom has 8 protons.

Almost all the atom’s mass is in its tiny nucleus.

Electrons take part in ordinary chemical bonds.

Helium exists as separate atoms. Oxygen usually exists as O₂ molecules.

Ordinary hydrogen, ¹H, has 1 proton and no neutron.

Why neutral?

A neutral atom has equal numbers of protons and electrons. In carbon, 6 positive charges balance 6 negative charges. The overall charge is zero. Opposite charges attract. Like charges repel.

Remember: O is an oxygen atom; O₂ is an oxygen molecule containing two atoms.

Molecule

Definition

A molecule is an electrically neutral group of two or more chemically bonded atoms.

Understand it simply

Atoms join by chemical bonds to make a molecule. Count the atoms to see how many are joined.

Examples

O₂ has 2 oxygen atoms. H₂O has hydrogen and oxygen atoms. A small lower-right number is a subscript. It counts atoms. CO₂ has 1 C and 2 O atoms: 3 atoms altogether.

Classification

Basis

Type

Meaning and examples

Atomicity: atoms per molecule

Diatomic

2 atoms: H₂, N₂, O₂, Cl₂, Br₂, I₂

Atomicity

Triatomic

3 atoms: H₂O, CO₂, O₃

Atomicity

Polyatomic

More than 2 atoms: NH₃, CH₄, P₄, S₈; includes triatomic molecules

Composition

Homoatomic

One element: O₂, O₃, P₄, S₈

Composition

Heteroatomic

Different elements: H₂O, CO₂, NH₃

One molecule can fit two groups. H₂O is triatomic because it has 3 atoms. It is also heteroatomic because it contains different elements. O₃ has 3 atoms of the same element, so it is triatomic and homoatomic.

Monatomic means one atom. He, Ne, Ar, Kr, Xe and Rn exist as individual atoms. They are often called monatomic species.

INTERACTIVE SCIENCE MODEL

Build a clear picture of each molecule

Choose a stage. Press Play to observe the movement.

He1 atom · 1 element

He. He is one atom: a monatomic species, not a bonded molecule.

Schematic model. Colours distinguish particles; sizes and speeds are illustrative. Animation starts only when you press Play.

View reference diagram
Colours distinguish elements. Models show atom counts and connectivity; positions and sizes are schematic.
Colours distinguish elements. Models show atom counts and connectivity; positions and sizes are schematic.
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Colours distinguish elements. Models show atom counts and connectivity; positions and sizes are schematic.

Count all the atoms, not just the different symbols. NH₃ contains 2 elements but 4 atoms.

Element

Definition

An element is a pure substance whose atoms have the same number of protons. It cannot be broken into simpler substances by ordinary chemical reactions.

Understand it simply

An element contains only one kind of atom. Oxygen gas is an element because every atom in it is oxygen.

Example

Copper and oxygen are elements. O₂ still counts as an element because all its atoms are oxygen.

Types of elements

Type

General properties

Examples

Metal

Usually shiny, malleable, ductile; good heat/electricity conductor

Fe, Cu, Al

Non-metal

Usually a poor conductor; solid forms generally brittle

S, O, C

Metalloid

Some metallic and some non-metallic properties

B, Si, Ge

Lustre means shine. Malleable means able to form sheets. Ductile means able to form wires. Brittle means likely to break rather than bend. A conductor lets heat or electric charge pass easily.

Silicon is a semiconductor: we can control how well it carries electric charge.

Most elements are solid at room temperature. Mercury is a liquid metal. Bromine is a liquid non-metal. Hydrogen, nitrogen and oxygen are gases. Graphite is a non-metal that conducts electricity.

An element is free when it is not combined with another element, as in Au or O₂. It is combined when it is part of a compound, as oxygen is in H₂O.

Chemical symbols

Write the first letter of a symbol as a capital. Write the second letter in lowercase: H, He, Na, Cl. Co means cobalt. CO means carbon monoxide.

GUIDED DIAGRAM

Reading element symbols

Explore each part · follow the explanation

1 / 3

Carbon. C is carbon. Its atomic number, 6, is the number of protons.

Choose a part for its explanation. Use Focus to enlarge it, or view the whole diagram to see every connection.

View complete static diagram
The upper number is atomic number. Capitalization changes meaning: Co and CO represent different substances.
The upper number is atomic number. Capitalization changes meaning: Co and CO represent different substances.
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The upper number is atomic number. Capitalization changes meaning: Co and CO represent different substances.

Element

Latin name

Symbol

Sodium

Natrium

Na

Potassium

Kalium

K

Iron

Ferrum

Fe

Copper

Cuprum

Cu

First 30 elements

Atomic number is the proton count, which identifies the element.

Atomic number

Element

Symbol

Atomic number

Element

Symbol

1

Hydrogen

H

16

Sulfur

S

2

Helium

He

17

Chlorine

Cl

3

Lithium

Li

18

Argon

Ar

4

Beryllium

Be

19

Potassium

K

5

Boron

B

20

Calcium

Ca

6

Carbon

C

21

Scandium

Sc

7

Nitrogen

N

22

Titanium

Ti

8

Oxygen

O

23

Vanadium

V

9

Fluorine

F

24

Chromium

Cr

10

Neon

Ne

25

Manganese

Mn

11

Sodium

Na

26

Iron

Fe

12

Magnesium

Mg

27

Cobalt

Co

13

Aluminium

Al

28

Nickel

Ni

14

Silicon

Si

29

Copper

Cu

15

Phosphorus

P

30

Zinc

Zn

Compound

Definition

A compound is a pure substance formed when different elements chemically combine in a fixed proportion.

Understand it simply

Different elements join in a set ratio to make a compound. Water always has 2 hydrogen atoms for every oxygen atom.

Example: water

H₂O has 2 H atoms for every O atom. The atom ratio is 2:1. But H and O have different masses. Using H = 1 and O = 16, the mass ratio is 2:16, or 1:8. Atom ratio and mass ratio are not the same.

Essential properties

A compound has a fixed composition.

Its properties differ from those of its elements.

Physical methods cannot separate it into its elements. A suitable chemical change is needed.

Molecules, ions and formula units

Water, CO₂ and NH₃ contain separate molecules. Solid ionic compounds contain positive and negative ions in a repeating three-dimensional pattern. This pattern is a crystal lattice.

Solid NaCl does not contain separate NaCl molecules. Its formula gives a 1:1 ratio of Na⁺ to Cl⁻. MgCl₂ gives a 1:2 ratio of Mg²⁺ to Cl⁻. A formula shows the elements and their numbers or simplest ion ratio.

Common compounds

Compound

Formula

Water

H₂O

Carbon dioxide

CO₂

Ammonia

NH₃

Sodium chloride

NaCl

Sodium hydroxide

NaOH

Silicon dioxide

SiO₂

Calcium oxide

CaO

Calcium carbonate

CaCO₃

Sulfuric acid

H₂SO₄

Sucrose

C₁₂H₂₂O₁₁

Sodium carbonate

Na₂CO₃

Washing soda

Na₂CO₃·10H₂O

Sodium hydrogen carbonate

NaHCO₃

Washing soda is Na₂CO₃·10H₂O. The dot shows water present in a fixed ratio in the crystal. This is water of crystallization. Anhydrous Na₂CO₃ has none of this water.

Salts in daily life

Use

Examples or explanation

Food flavouring

Sodium chloride

Food preservation

Certain salts, such as sodium nitrite, sodium sulfite and sodium citrate, are used for suitable purposes

Fertilizers

Ammonium sulfate and ammonium nitrate supply plant nutrients

Traditional photography

Light-sensitive silver salts

Plaster casts

Plaster of Paris, calcium sulfate hemihydrate, CaSO₄·½H₂O, sets after mixing with water

Chemical industry

Sodium chloride is an important raw material

A salt is an ionic compound of cations and anions. Plaster of Paris is CaSO₄·½H₂O: one water molecule per two CaSO₄ units, on average.

Pure substances and mixtures

Elements and compounds are pure substances. A mixture contains substances physically combined in variable proportions; its components retain their chemical identities.

GUIDED DIAGRAM

Classification of matter

Explore each part · follow the explanation

Complete view keeps labels and connections together1 / 5

Pure substances. A pure substance has a fixed composition. Elements and compounds are pure substances.

Choose a part for its explanation. Use Focus to enlarge it, or view the whole diagram to see every connection.

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Elements and compounds are pure substances. Mixtures may have uniform or non-uniform composition.
Elements and compounds are pure substances. Mixtures may have uniform or non-uniform composition.
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Elements and compounds are pure substances. Mixtures may have uniform or non-uniform composition.

Mixture

Composition

Examples

Homogeneous

Uniform throughout

Salt solution, clean dry air

Heterogeneous

Non-uniform; different regions or phases

Sand and water, oil and water, blood

Blood has cells suspended in liquid plasma. Blood plasma is not the plasma state of matter.

INTERACTIVE MODEL

How mixture composition differs

Change the model · explore the parts

1 · PREDICT

What changes when you choose Heterogeneous instead of Homogeneous?

Choose what you expect, then test it below. You can explore without answering first.

2 · TRY IT

Both colours represent different components. There are 30 particles in total.

Switch between Homogeneous and Heterogeneous. Compare different regions of the container.
30 particles · schematic arrangement

Colours distinguish components. Their distribution changes, but their total numbers remain the same.

Change a control and watch what changes—and what stays the same.
3 · EXPLAIN

Change the controls to see the result. Choose Explore diagram parts for a guided explanation.

View complete static diagram
Both boxes contain two components. A homogeneous mixture is evenly mixed; a heterogeneous mixture has distinct regions.
Both boxes contain two components. A homogeneous mixture is evenly mixed; a heterogeneous mixture has distinct regions.
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Both boxes contain two components. A homogeneous mixture is evenly mixed; a heterogeneous mixture has distinct regions.

Separation methods

Method

Principle and example

Filtration

Filter retains insoluble solid: sand from water

Evaporation

Solvent changes into vapour, leaving dissolved solid: salt from solution

Crystallization

Crystals form from a suitable solution

Distillation

Liquid changes into vapour and its vapour condenses: water from salt solution

A solvent is a substance that dissolves another substance. Insoluble means that a substance dissolves very little in the given solvent. Condensation is the change from vapour to liquid.

Feature

Element

Compound

Mixture

Composition

One type of atom

Different elements in a fixed proportion

Substances in variable proportions

Pure substance?

Yes

Yes

No

Physical separation into components

Not applicable

Not possible

Possible by suitable methods

Chemical breakdown

Cannot form simpler substances by ordinary reactions

Can form simpler substances in suitable reactions

Not required for physical separation

Example

Copper

Pure water

Salt solution

Looking uniform does not prove that a substance is pure. Salt solution is uniform, but it is a mixture.

Ion

Definition

An ion is an atom or group of atoms with a net electric charge.

Understand it simply

Protons are positive and electrons are negative. If their numbers do not balance, the particle has a charge.

Formation and examples

Type

Formation from a neutral atom

Example

Cation: positive ion

Electron loss

Na → Na⁺ + e⁻

Anion: negative ion

Electron gain

Cl + e⁻ → Cl⁻

Na⁺ has 11 protons and 10 electrons. Cl⁻ has 17 protons and 18 electrons. Making these ions changes electrons, not protons. Losing a negative electron makes an atom more positive.

GUIDED DIAGRAM

Making ions from neutral atoms

Explore each part · follow the explanation

1 / 2

Lose an electron. Na loses one electron to form Na⁺. It still has 11 protons but now has 10 electrons.

Choose a part for its explanation. Use Focus to enlarge it, or view the whole diagram to see every connection.

View complete static diagram
Loss of electrons forms a positive ion; gain forms a negative ion. The element remains unchanged.
Loss of electrons forms a positive ion; gain forms a negative ion. The element remains unchanged.
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Loss of electrons forms a positive ion; gain forms a negative ion. The element remains unchanged.

A superscript is a small raised symbol. Mg²⁺ has charge +2. O²⁻ has charge −2. A monatomic ion is one charged atom. A polyatomic ion is a charged group of bonded atoms.

Common polyatomic ions

Name

Formula

Overall charge

Ammonium

NH₄⁺

+1

Hydroxide

OH⁻

−1

Nitrate

NO₃⁻

−1

Carbonate

CO₃²⁻

−2

Sulfate

SO₄²⁻

−2

The charge belongs to the whole polyatomic ion. It is not the charge on each atom.

Molecular ion

A molecular ion forms when a molecule gains or loses electron(s) while remaining together: O₂ + e⁻ → O₂⁻. “Polyatomic” describes composition; “molecular ion” emphasizes formation from a molecule.

Free radical

A free radical contains at least one unpaired electron. Examples: H•, Cl•, CH₃•. The dot represents an unpaired electron, not electric charge.

An unpaired electron has no partner in its orbital. An orbital describes where an electron is likely to be found. A bond can split so that each atom takes 1 electron from the shared pair. This is homolytic cleavage. Suitable light can cause Cl₂ → 2Cl•.

Ion = net charge; radical = unpaired electron. Some species, such as O₂⁻, have both. A chemical species is a particular kind of atom, molecule, ion or radical.

Valency

Valency is the combining capacity of an atom. In simple compounds, it is related to how many electrons the atom loses, gains or shares. Oxygen has valency 2 in H₂O; carbon has valency 4 in CH₄.

Elements

Common valencies used at this level

H, Li, Na, K, F

1

Be, Mg, Ca, Zn, O

2

B, Al

3

C, Si

4

He, Ne, Ar

0 in ordinary elementary examples

N

Usually 3 in simple covalent examples

P

3, 5

S

2, 4, 6 in classical formula-writing tables

Cl

Commonly 1; also 3, 5, 7 in classical tables

Fe

2, 3

Cu

1, 2

Some elements have different valencies in different compounds. This is variable valency. Valency has no + or − sign. Mg has valency 2; Mg²⁺ has charge 2+. Oxidation number follows separate electron-counting rules and can have a sign.

Writing ionic formulae

Balance total positive and negative charges, then use the simplest whole-number ion ratio.

Ions

Charge balance

Formula

Mg²⁺, Cl⁻

1(+2) + 2(−1) = 0

MgCl₂

Al³⁺, O²⁻

2(+3) + 3(−2) = 0

Al₂O₃

Ca²⁺, OH⁻

1(+2) + 2(−1) = 0

Ca(OH)₂

Use brackets around a polyatomic ion that repeats. Ca(OH)₂ has 1 Ca, 2 O and 2 H atoms. Use the simplest ratio: MgO, not Mg₂O₂. Leave ionic charges out of a neutral compound’s formula.

Atomic Number

Definition

Atomic number, Z, is the number of protons in an atom’s nucleus.

Understand it simply

To find the atomic number, count protons. The number of neutrons does not affect it.

Example

Every oxygen atom has 8 protons, so Z = 8. Gaining electrons to form O²⁻ does not change Z.

Particle counts

Neutral atom: electrons = protons = Z.

Cation: electrons = Z − positive charge number.

Anion: electrons = Z + negative charge magnitude.

Species

Z

Protons

Electrons

Reason

Na

11

11

11

Neutral

Na⁺

11

11

10

Lost one electron

Mg²⁺

12

12

10

Lost two electrons

Cl⁻

17

17

18

Gained one electron

O²⁻

8

8

10

Gained two electrons

Remember: Z always counts protons. It equals electron number only for a neutral atom.

Mass Number and Atomic Mass

Mass number

Mass number, A, is the total number of protons and neutrons in one nucleus. Protons and neutrons together are called nucleons.

Understand it simply

Count protons and neutrons together to find A. To find neutrons alone, subtract Z from A.

A = protons + neutrons

Z = protons

Neutrons = A − Z

Mass number counts particles, so it is a whole number without a unit. Write A at the upper left of the element symbol. Write Z at the lower left.

INTERACTIVE MODEL

Atomic number and mass number

Change the model · explore the parts

1 · PREDICT

Choose a heavier isotope of the same element. What must change?

Choose what you expect, then test it below. You can explore without answering first.

2 · TRY IT

Start with the selected neutral atom. Compare its proton, neutron and electron counts.

Choose the isotope with the next higher mass number. Read A, Z and the three particle counts.
NaNa2311A = 23; Z = 11Neutral: charge 0Shells: 2, 8, 1
Protons11
Neutrons12
Electrons11

Changing the isotope changes neutrons and mass number. Proton number and the neutral atom’s electron count stay fixed. Shell rings are a model, not literal paths.

Change a control and watch what changes—and what stays the same.
3 · EXPLAIN

Change the controls to see the result. Choose Explore diagram parts for a guided explanation.

View complete static diagram
A is placed at the upper left and Z at the lower left of the symbol. These are particle counts, with no units.
A is placed at the upper left and Z at the lower left of the symbol. These are particle counts, with no units.
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A is placed at the upper left and Z at the lower left of the symbol. These are particle counts, with no units.

Worked particle counts

Given

Protons

Neutrons

Electrons

11 protons, 12 neutrons

Z = 11

12; A = 11 + 12 = 23

11 if neutral

A = 40, Z = 20

20

40 − 20 = 20

20 if neutral

²³Na⁺; Z = 11

11

23 − 11 = 12

11 − 1 = 10

Isotopes

Isotopes are atoms of the same element with different neutron numbers: same Z, different A. Chlorine-35 and chlorine-37 both have 17 protons, but 18 and 20 neutrons respectively.

Atomic mass and relative atomic mass

Quantity

Meaning

Unit

Atomic mass

Mass of an atom

Usually u

Unified atomic mass unit, u

One-twelfth of a carbon-12 atom’s mass

1 u ≈ 1.66 × 10⁻²⁴ g

Relative atomic mass, Ar

Average atomic mass divided by 1 u

None

Carbon-12 has mass exactly 12 u. Mass number counts protons and neutrons. Atomic mass measures mass. Relative atomic mass is an average that gives more weight to the more common isotopes. Abundance tells us how common an isotope is.

Weighted-average example

For a simplified sample with 75% chlorine-35 and 25% chlorine-37:

Ar = (75/100 × 35) + (25/100 × 37)

= 26.25 + 9.25 = 35.5.

The result is nearer 35 because that isotope is more abundant.

Molecular mass and formula mass

Molecular mass = sum of atomic masses in one molecule. Formula mass = sum of atomic masses in one formula unit; used for ionic compounds, which have no separate molecules. Both are expressed in u.

Example: HNO₃

Given: H = 1 u, N = 14 u, O = 16 u.

Count: 1 H, 1 N, 3 O.

Molecular mass = 1(1) + 1(14) + 3(16)

= 1 + 14 + 48 = 63 u.

Example: Al₂(SO₄)₃

Given: Al = 27 u, S = 32 u, O = 16 u.

Count: 2 Al; 3 S; 3 × 4 = 12 O.

Formula mass = 2(27) + 3(32) + 12(16)

= 54 + 96 + 192 = 342 u.

Using Al = 26.98 u instead gives 341.96 u. Use the supplied atomic masses.

Relative molecular mass, Mr, is molecular mass divided by 1 u: its numerical value is the same, but it has no unit. H₂O: molecular mass ≈ 18 u; Mr ≈ 18.

Empirical and molecular formulae

Formula

Shows

Glucose example

Empirical

Simplest whole-number atom ratio

CH₂O

Molecular

Actual atom numbers per molecule

C₆H₁₂O₆

For glucose, divide all three numbers in 6:12:6 by 6. The simplest ratio is 1:2:1. Different compounds can have the same simplest ratio.

Compound

Molecular formula

Empirical formula

Carbon dioxide

CO₂

CO₂

Hydrogen peroxide

H₂O₂

HO

Benzene

C₆H₆

CH

Glucose

C₆H₁₂O₆

CH₂O

Acetic acid

C₂H₄O₂

CH₂O

CH₃COOH shows how some atoms are grouped in acetic acid. Counting all its atoms gives the molecular formula C₂H₄O₂.

Finding a molecular formula

Molecular formula = (Empirical formula)ₙ

n = molecular mass / empirical formula mass.

Here n is a positive whole-number multiplier; in mole calculations, n instead denotes amount of substance.

Example: Empirical formula CH₂O; molecular mass 180 u.

Empirical formula mass = 12 + 2(1) + 16 = 30 u.

n = 180/30 = 6.

Multiply every subscript by 6: C₁H₂O₁ → C₆H₁₂O₆.

Mole

Definition

One mole is the amount of substance containing exactly 6.02214076 × 10²³ specified entities. An entity is the atom, molecule, ion or formula unit being counted.

Understand it simply

A dozen counts 12 items. A mole counts a much larger fixed number. Always name what you are counting.

Avogadro constant: NA = 6.02214076 × 10²³ mol⁻¹ exactly. The unit mol⁻¹ means per mole. Calculations here use the book’s rounded value 6.02 × 10²³ mol⁻¹.

Same count, different masses

Amount

Specified entities

Approximate mass

1 mol O atoms

NA oxygen atoms

16 g

1 mol O₂ molecules

NA molecules; 2NA O atoms

32 g

1 mol H₂O molecules

NA water molecules

18 g

1 mol NaCl

NA formula units

58.5 g

10²³ means 1 followed by 23 zeros. Scientific notation helps us write very large or small numbers. It uses a number from 1 to less than 10, multiplied by a power of 10.

Molar mass and textbook terms

Molar mass, M, is mass per mole, usually in g mol⁻¹. One H₂O molecule has mass about 18 u; one mole has mass about 18 g, so M ≈ 18 g mol⁻¹.

Term

Meaning

Example

Gram atomic mass

Mass of one mole of atoms

16 g of O atoms

Gram molecular mass

Mass of one mole of molecules

32 g of O₂ molecules

Gram formula mass

Mass of one mole of formula units

58.5 g of NaCl

Core relationships

n = m/M; m = nM

N = nNA; n = N/NA

Therefore N = (m/M)NA.

n is moles; m is mass in grams; M is molar mass in g mol⁻¹; N counts the named particles. To find moles, divide the sample’s mass by the mass of 1 mole.

GUIDED DIAGRAM

Moles connect measurable quantities

Explore each part · follow the explanation

1 / 3

Mass ↔ moles. Divide mass by molar mass to find moles: n = m/M. Multiply moles by molar mass to find mass: m = nM.

Choose a part for its explanation. Use Focus to enlarge it, or view the whole diagram to see every connection.

View complete static diagram
Use moles to connect mass, specified particle count and gas volume. Always state the particle type and gas conditions.
Use moles to connect mass, specified particle count and gas volume. Always state the particle type and gas conditions.
Diagram viewer
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Use moles to connect mass, specified particle count and gas volume. Always state the particle type and gas conditions.

1. Moles in 40 g Na

Given: m = 40 g; M = 23 g mol⁻¹. Find n.

n = m/M = 40 g / (23 g mol⁻¹)

= 1.739… mol ≈ 1.74 mol Na.

Grams cancel, leaving mol.

2. Mass of 4 mol CO₂

Given: n = 4 mol. Find m.

M = 12 + 2(16) = 44 g mol⁻¹.

m = nM = 4 mol × 44 g mol⁻¹ = 176 g CO₂.

3. Atoms in 9.2 g Ca

Given: m = 9.2 g; M = 40 g mol⁻¹. Find N.

First convert mass to moles: n = 9.2/40 = 0.23 mol.

Then count atoms: N = nNA = 0.23 × 6.02 × 10²³

= 1.3846 × 10²³ ≈ 1.38 × 10²³ Ca atoms.

4. Moles and molecules in 8 g glucose

Given: m = 8 g; C₆H₁₂O₆. Find n and N.

M = 6(12) + 12(1) + 6(16)

= 72 + 12 + 96 = 180 g mol⁻¹.

n = m/M = 8/180 = 0.04444… mol.

N = (8/180) × 6.02 × 10²³

≈ 2.68 × 10²² molecules.

Keep the unrounded fraction until the final answer.

5. Moles in 8.5 g silver

Assume the stated mass is silver. Using the supplied M = 107 g mol⁻¹:

n = m/M = 8.5 g / (107 g mol⁻¹)

≈ 0.0794 mol Ag.

If M = 108 g mol⁻¹ is supplied instead, n ≈ 0.0787 mol.

6. Moles, molecules and atoms in 10 g H₂SO₄

Given: m = 10 g. Find n, molecules and total atoms.

M = 2(1) + 32 + 4(16) = 98 g mol⁻¹.

n = m/M = 10/98 ≈ 0.102 mol.

Molecules = (10/98) × 6.02 × 10²³ ≈ 6.14 × 10²².

Each molecule has 2 + 1 + 4 = 7 atoms.

Total atoms = 7 × (10/98) × 6.02 × 10²³ ≈ 4.30 × 10²³.

For oxygen atoms only, multiply the molecule count by 4.

Formula units and ions

1 mol NaCl contains 1 mol Na⁺ and 1 mol Cl⁻. That is 2 mol ions altogether. It is still only 1 mol NaCl.

Mole–volume calculations

Here STP means 0 °C and 1 atm. At these conditions, 1 mole of an ideal gas occupies about 22.4 L. Some sources use 1 bar for STP, so always check the conditions. An ideal gas is a simplified model.

V = n × 22.4 L mol⁻¹

n = V / (22.4 L mol⁻¹)

1 L = 1 dm³. Do not apply this molar volume to liquids or solids.

Additional practice: 0.5 mol O₂

Given: n = 0.5 mol at 0°C and 1 atm. Find V.

V = n × 22.4 L mol⁻¹

= 0.5 mol × 22.4 L mol⁻¹ = 11.2 L.

7. CO₂ from 0.450 mol CO

Given: excess O₂; 0°C and 1 atm. Find CO₂ volume. Excess means more reactant than required.

Equation: 2CO + O₂ → 2CO₂.

Mole ratio CO : CO₂ = 2 : 2 = 1 : 1.

So 0.450 mol CO forms 0.450 mol CO₂.

V = 0.450 × 22.4 = 10.08 L ≈ 10.1 L.

Coefficients give mole ratios; they do not give direct mass ratios.

Chemical Reaction and Equation

Chemical reaction

A chemical reaction forms new substances through rearrangement of atoms and changes in bonding. Reactants are starting substances; products are substances formed.

Understand it simply

In a chemical reaction, atoms join in new ways. The starting substances change into new substances.

Chemical equation

A chemical equation represents a reaction using symbols and formulae: reactants → products.

Example: 2H₂(g) + O₂(g) → 2H₂O(l).

Two hydrogen molecules react with one oxygen molecule to form two water molecules. Mole ratio = 2 : 1 : 2.

GUIDED DIAGRAM

Reading a chemical equation

Explore each part · follow the explanation

1 / 4

Reactants and product. Hydrogen and oxygen are reactants, written on the left. Water is the product, written on the right.

Choose a part for its explanation. Use Focus to enlarge it, or view the whole diagram to see every connection.

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The coefficient multiplies the entire formula. Subscripts identify composition and must stay unchanged during balancing.
The coefficient multiplies the entire formula. Subscripts identify composition and must stay unchanged during balancing.
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The coefficient multiplies the entire formula. Subscripts identify composition and must stay unchanged during balancing.

Symbols

Symbol

Meaning

+

Separates substances on the same side; read as “reacts with” on the reactant side

→

Produces

⇌

Forward and reverse reactions are possible

(s)

Solid

(l)

Liquid

(g)

Gas

(aq)

Aqueous: dissolved in water

Δ above the arrow

Heating

Aqueous means dissolved in water. A reversible reaction can go in both directions. A catalyst changes reaction speed without being used up overall. Show it above or below the arrow.

Coefficient versus subscript

A coefficient multiplies the whole formula. So 2H₂O has 4 H and 2 O atoms. A subscript is part of the formula. H₂O₂ is different from H₂O. When balancing, change coefficients only.

Why balance?

The law of conservation of mass states that the total mass remains unchanged during a chemical reaction in a closed system. A closed system does not exchange matter with its surroundings.

Therefore, each element must have the same number of atoms on both sides of the equation.

Inspection method

1. Write the correct formulas.

2. Count each kind of atom on both sides.

3. Change coefficients until the counts match.

4. Use the smallest whole-number ratio.

5. Check every element again.

Worked example: potassium chlorate

Heating KClO₃ produces KCl and O₂.

1. Skeleton equation: KClO₃ → KCl + O₂.

2. K and Cl match; O counts are 3 and 2.

3. Make O counts 6: 2KClO₃ → KCl + 3O₂.

4. Balance K and Cl: 2KClO₃ → 2KCl + 3O₂.

5. Check: K = 2, Cl = 2, O = 6 on each side.

Final: 2KClO₃(s) → 2KCl(s) + 3O₂(g), with Δ above the arrow to indicate heating. Use the actual substance formula—oxygen gas is O₂, not O.

Branches of Chemistry

Understand it simply

Each branch studies part of chemistry. The branches often work together.

Branch

Main focus

Example

Physical

Physical principles governing chemical behaviour: energy, gases and reaction rates

Effect of temperature on reaction speed

Organic

Structures, properties, preparation and reactions of organic carbon compounds

Fuels, alcohols, plastics

Inorganic

Elements and inorganic compounds

Metals, salts, minerals, ceramics

Biochemistry

Substances and reactions in living organisms

Proteins, fats, digestion

Industrial

Large-scale chemical manufacturing

Fertilizers, cement, medicines

Nuclear

Nuclear properties, radioactivity and transformations

Cancer treatment; nuclear power

Environmental

Chemical processes and substances in the environment

Pollutants in air and water

Analytical

Identifying substances and measuring their amounts

Measuring salt in a sample

Medicinal

Design, preparation and improvement of drugs

Developing an effective medicine

Quantum

Applying quantum mechanics to chemical systems

Electron states and bonding

Green

Designing products/processes that reduce or eliminate hazardous substances

Safer solvents, less waste and energy use

Essential terms and distinctions

Hydrocarbon: contains only carbon and hydrogen. Derivative: a related compound formed by replacing atom(s) or groups. CO, CO₂, carbonates, hydrogen carbonates and many cyanides are usually studied in inorganic chemistry.

Mineral: naturally occurring solid with characteristic composition and structure. Metallurgy: extracting and processing metals. Ore: material from which a useful component can be extracted economically.

Biomolecules: molecules associated with living organisms. Metabolism: all chemical reactions in an organism. Radioactivity: spontaneous change of unstable nuclei with emission of radiation.

Qualitative analysis asks: “Which substances are present?” Quantitative analysis asks: “How much is present?” Chromatography separates substances because they travel at different rates through a material. Electrophoresis separates charged particles using an electric field. Spectroscopy studies how matter interacts with radiation, such as light.

Quantum mechanics explains matter and energy on very small scales. Hazardous means able to cause harm. Green chemistry aims to prevent waste and hazards. Environmental chemistry studies chemicals in the environment and their effects.

Historical Background

Understand it simply

Early thinkers used reasoning to explain matter. Modern chemistry grew through experiments and measurements. A hypothesis is an explanation we can test. A scientific theory is an explanation strongly supported by evidence.

Early ideas and practical chemistry

Scientist or thinker

Contribution

Democritus

Proposed that matter consists of tiny indivisible particles called atoms

Plato

Developed philosophical ideas about elements and geometric forms

Aristotle

Supported the four-element model: earth, water, air and fire

Jabir ibn Hayyan

Associated with early experimental methods, chemical preparations and metal extraction

Al-Razi

Contributed to practical chemistry, descriptions of substances and medicine

Al-Biruni

Investigated densities of different substances

Ibn Sina

Made major contributions to medicine and related natural philosophy

Gases and modern chemical ideas

Scientist

Contribution

Robert Boyle

Studied the pressure–volume relation of gases and promoted experimental investigation

Joseph Black

Studied carbon dioxide, historically called “fixed air”

Joseph Priestley

Independently prepared oxygen and investigated several gases

Carl Wilhelm Scheele

Independently prepared oxygen and prepared chlorine

Henry Cavendish

Identified hydrogen as a distinct gas

Antoine Lavoisier

Explained combustion using oxygen and helped establish quantitative chemistry

John Dalton

Proposed a modern atomic theory of matter

Jacques Charles

Studied how gas volume changes with temperature

Joseph Louis Gay-Lussac

Studied simple whole-number ratios of reacting gas volumes

Amedeo Avogadro

Proposed that equal gas volumes at the same temperature and pressure contain equal numbers of molecules

Notation, periodic arrangement and electricity

Scientist

Contribution

Dulong and Petit

Established an approximate relation for the molar heat capacities of many solid elements

J. J. Berzelius

Developed modern chemical-symbol notation

Dmitri Mendeleev

Developed a periodic arrangement of elements

Svante Arrhenius

Proposed electrolyte dissociation and an acid–base theory

Michael Faraday

Established laws of electrolysis and contributed to the study of electromagnetism

Atomic structure and quantum ideas

Scientist

Contribution

J. J. Thomson

Discovered the electron

Ernest Rutherford

Established the nuclear model; distinguished alpha and beta radiation and investigated radioactive change

Niels Bohr

Proposed quantized electron energy levels for hydrogen

Louis de Broglie

Proposed the wave nature of matter

Erwin Schrödinger

Developed a wave-mechanical description of atoms

S. N. Bose and Albert Einstein

Developed theory underlying Bose–Einstein condensation

Eric Cornell and Carl Wieman, with their team

Produced a dilute-gas Bose–Einstein condensate

Democritus suggested indivisible particles. Much later, Dalton developed a scientific atomic theory. These were different stages in our understanding of atoms.

Combustion = burning, usually with oxygen. Heat capacity = energy needed for a specified temperature rise. Periodic = recurring in a pattern. An electrolyte supplies mobile ions in solution or when molten; dissociation separates particles such as ions; electrolysis uses electricity to drive chemical change.

Quantized energy allows only certain energy values. Bose–Einstein condensation happens at extremely low temperatures. It is different from plasma, which contains mobile charged particles.

States of Matter

Understand it simply

A state of matter is a physical form, such as solid, liquid or gas. It depends on how particles are arranged, how they move and how they attract one another.

Property

Solid

Liquid

Gas

Shape

Definite

Container’s shape

Fills container

Volume

Definite

Definite

Not definite

Particles

Close; vibrate about fixed positions

Close; move past one another

Far apart; move freely

Compressibility

Very low

Very low

High

Water example

Ice

Liquid water

Water vapour

Compressibility tells us how easily volume decreases under pressure. Gases are easy to compress because their particles have large spaces between them.

Plasma

Plasma has moving electrons and positive ions. Adding enough energy can remove electrons from gas atoms. This is ionization. Stars and lightning contain plasma.

INTERACTIVE MODEL

Particle models of matter

Change the model · explore the parts

1 · PREDICT

When a solid becomes a liquid, what mainly changes in this particle model?

Choose what you expect, then test it below. You can explore without answering first.

2 · TRY IT

The model contains 30 particles. Start with Solid.

Press Play movement, then choose Liquid and Gas. Compare spacing and movement.
30 particles · schematic arrangement

Solid particles vibrate close to fixed positions.

Change a control and watch what changes—and what stays the same.
3 · EXPLAIN

Change the controls to see the result. Choose Explore diagram parts for a guided explanation.

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Particle arrangements are schematic. Heating can melt or vaporize matter; sufficiently energetic conditions can ionize a gas into plasma.
Particle arrangements are schematic. Heating can melt or vaporize matter; sufficiently energetic conditions can ionize a gas into plasma.
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Particle arrangements are schematic. Heating can melt or vaporize matter; sufficiently energetic conditions can ionize a gas into plasma.

Changes of state

Melting: solid → liquid. Freezing: liquid → solid.

Vaporization: liquid → gas. Condensation: gas → liquid.

Heating usually makes particles move faster. During melting or boiling, energy can change the arrangement without raising temperature. Ice, liquid water and water vapour are all H₂O. Changing state does not make a new substance.

Exercise: Short Questions

1. Differentiate between physical and analytical chemistry.

Physical chemistry

Analytical chemistry

Studies physical principles governing chemical behaviour

Identifies substances and measures their amounts

Includes energy changes, gas behaviour and reaction rates

Includes qualitative and quantitative analysis

Example: Effect of temperature on reaction speed

Example: Amount of salt in drinking water

2. Write the classification of molecules.

Molecules can be classified by atomicity and by the type of atoms present.

By atomicity: Diatomic, triatomic and other polyatomic molecules.

By composition: Homoatomic and heteroatomic molecules.

H₂O is triatomic because it has three atoms and heteroatomic because it has two different elements.

Helium, neon and argon are monatomic species: they exist as individual atoms.

3(a). Differentiate between an atom and an ion.

Atom

Ion

Electrically neutral

Has a net positive or negative charge

Proton and electron numbers are equal

Positive and negative charges do not balance

Example: Na

Example: Na⁺

When Na loses one electron it becomes Na⁺. The proton count remains unchanged.

3(b). Differentiate between a molecule and a molecular ion.

A molecule is electrically neutral. A molecular ion is a charged species formed when a molecule gains or loses electron(s) while its atoms remain together.

Example: O₂ is a molecule; O₂⁻ is a molecular ion.

3(c). Differentiate between a compound and a mixture.

Compound

Mixture

Elements are chemically combined

Substances are physically combined

Has a fixed composition

Composition can vary

Has properties different from those of the elements that form it

Components retain their chemical identities

Cannot be separated into elements by physical methods

Can be separated by suitable physical methods

Example: Pure H₂O

Example: Salt solution

4. Define gram atomic mass, gram molecular mass and gram formula mass.

Gram atomic mass: Mass of one mole of atoms. Example: About 12 g of carbon atoms.

Gram molecular mass: Mass of one mole of molecules. Example: About 18 g of H₂O molecules.

Gram formula mass: Mass of one mole of formula units. Example: About 58.5 g of NaCl.

These are textbook terms. Molar mass expresses the corresponding mass per mole, in g mol⁻¹.

5. Write chemical, empirical and molecular formulae.

A chemical formula is the general representation of composition. A molecular formula gives actual atoms per molecule; an empirical formula gives their simplest ratio.

Compound

Molecular formula

Empirical formula

Sulfuric acid

H₂SO₄

H₂SO₄

Carbon dioxide

CO₂

CO₂

Glucose

C₆H₁₂O₆

CH₂O

Benzene

C₆H₆

CH

The subscripts of H₂SO₄ and CO₂ have no common factor greater than 1, so their empirical and molecular formulae are the same.

6. What is a free radical?

A free radical is an atom or group of atoms containing at least one unpaired electron.

Examples: H•, Cl• and CH₃•.

The dot represents an unpaired electron; it does not represent an electric charge.

7. Relate empirical and molecular formulae with an example.

Molecular formula = (Empirical formula)ₙ, where n is a positive whole-number multiplier.

For benzene, C₆H₆ reduces from 6 : 6 to 1 : 1, so its empirical formula is CH.

Its molecular formula is (CH)₆ = C₆H₆. Every subscript is multiplied by 6.

8. Why are hydrogen and oxygen elements, but water a compound?

H₂ contains only hydrogen atoms. O₂ contains only oxygen atoms. Each is therefore an element.

H₂O contains two different elements chemically bonded in a fixed ratio. It is therefore a compound.

Exercise: Detailed Questions

1. Explain chemical species, ions, molecular ions and free radicals.

A chemical species is a particular kind of atom, molecule, ion or radical.

An ion carries a net electric charge. It may be one atom or a group of bonded atoms.

A cation has positive charge and forms by electron loss: Na → Na⁺ + e⁻.

An anion has negative charge and forms by electron gain: Cl + e⁻ → Cl⁻.

A molecular ion forms when a molecule gains or loses electron(s) without fragmenting. For example: O₂ + e⁻ → O₂⁻.

A free radical contains at least one unpaired electron, represented by a dot.

Suitable light causes chlorine to undergo homolytic cleavage: Cl₂ → 2Cl•.

Each chlorine takes one electron from the shared pair. Charge and an unpaired electron are different properties; a species may have both.

2. Explain applications of chemistry in daily life.

Chemistry helps us understand substances and their changes in homes, living organisms and industry.

Food: Cooking changes food; preservation delays spoilage; digestion breaks food into absorbable substances.

Health: Chemical research helps develop medicines. Biochemistry helps explain normal body processes and disease.

Agriculture: Fertilizers supply nutrients needed by crops.

Cleaning: Soaps and detergents help remove dirt and grease.

Water: Treatment removes impurities; suitable disinfection kills many harmful microorganisms.

Materials: Chemical industries produce glass, cement, plastics, paints and synthetic fibres.

3. Explain empirical and molecular formulae.

An empirical formula gives the simplest whole-number atom ratio of the elements in a compound.

A molecular formula gives the actual number of atoms of each element in one molecule.

For glucose, C₆H₁₂O₆ gives the atom ratio 6 : 12 : 6.

Dividing each number by 6 gives 1 : 2 : 1, so its empirical formula is CH₂O.

Molecular formula = (Empirical formula)ₙ.

The multiplier n is found by dividing molecular mass by empirical formula mass, with both in the same units.

For glucose: empirical formula mass = 30 u and molecular mass = 180 u.

n = 180 / 30 = 6; therefore, molecular formula = C₆H₁₂O₆.

For CO₂, n = 1. Thus, empirical and molecular formulae may be the same.

4. Explain the steps of balancing a chemical equation.

A balanced equation has equal atom counts for every element on both sides. This is consistent with conservation of mass.

Step 1: Write correct formulae: KClO₃ → KCl + O₂.

Step 2: Count atoms. K and Cl are equal, but O is 3 on the left and 2 on the right.

Step 3: Make oxygen counts 6: 2KClO₃ → KCl + 3O₂.

Step 4: Balance K and Cl: 2KClO₃ → 2KCl + 3O₂.

Step 5: Verify: both sides contain 2 K, 2 Cl and 6 O atoms.

Only coefficients are changed. Subscripts must remain those of the correct substances.

5. Name the branches of chemistry and discuss any five.

The branches listed in the textbook are physical, organic, inorganic, biochemistry, industrial, nuclear, environmental, analytical, medicinal, quantum and green chemistry.

Physical chemistry studies physical principles of chemical behaviour, including energy changes and reaction rates.

Organic chemistry studies organic carbon compounds, including hydrocarbons and their derivatives.

Inorganic chemistry studies elements and inorganic compounds such as metals, salts and minerals.

Biochemistry studies chemical substances and reactions in living organisms, including proteins and metabolism.

Analytical chemistry identifies substances and determines their amounts. It includes qualitative and quantitative analysis.

Exercise: Solved Numericals

Use the rounded atomic masses supplied in each question. For this exercise: H = 1, C = 12, N = 14, O = 16, Na = 23, Mg = 24, Al = 27, S = 32, Cl = 35.5, K = 39 and Ca = 40, in u.

For particle calculations use NA ≈ 6.02 × 10²³ mol⁻¹.

1(a). Balance NH₃ + O₂ → NO + H₂O.

Step 1: Inspect nitrogen and hydrogen.

NH₃ has three H atoms; H₂O has two. Choosing an even number of NH₃ molecules avoids a fractional H₂O coefficient.

Start with 4NH₃. This contains 4 N and 12 H atoms.

Step 2: Balance N.

Put 4 before NO.

Step 3: Balance H.

Twelve H atoms require 6H₂O.

Step 4: Balance O.

4NO contains 4 O atoms and 6H₂O contains 6 O atoms.

Total O atoms in products = 10, supplied by 5O₂.

Answer: 4NH₃ + 5O₂ → 4NO + 6H₂O

Check: N = 4, H = 12, O = 10 on each side.

1(b). Balance KNO₃ → KNO₂ + O₂.

Step 1: Put 2 before KNO₃ and KNO₂. K and N are then balanced at 2 each.

Step 2: Left O = 2 × 3 = 6. Oxygen in 2KNO₂ = 2 × 2 = 4.

Step 3: The remaining 2 O atoms form one O₂ molecule.

Answer: 2KNO₃ → 2KNO₂ + O₂

Check: K = 2, N = 2, O = 6 on each side.

1(c). Balance Ca + H₂O → Ca(OH)₂ + H₂.

Step 1: Ca is already balanced at one atom.

Step 2: Ca(OH)₂ contains two O atoms, so put 2 before H₂O.

Step 3: The left side now has four H atoms.

On the right, Ca(OH)₂ contains two H atoms and H₂ contains two more. Total H = 4.

Answer: Ca + 2H₂O → Ca(OH)₂ + H₂

Check: Ca = 1, O = 2, H = 4 on each side.

1(d). Balance NaHCO₃ → Na₂CO₃ + H₂O + CO₂.

Step 1: Na₂CO₃ contains two Na atoms, so put 2 before NaHCO₃.

Step 2: Count remaining atoms on the left: H = 2, C = 2, O = 6.

Step 3: On the right: H = 2; C = 1 + 1 = 2; O = 3 + 1 + 2 = 6.

Answer: 2NaHCO₃ → Na₂CO₃ + H₂O + CO₂

Every element is balanced.

1(e). Balance CO + O₂ → CO₂.

Step 1: Put 2 before CO₂ to make four O atoms on the right.

Step 2: Put 2 before CO to balance two C atoms.

Step 3: Oxygen on the left = 2 from 2CO + 2 from O₂ = 4.

Answer: 2CO + O₂ → 2CO₂

Check: C = 2 and O = 4 on each side.

2(a). Calculate the formula mass of Al₂O₃.

Given: Al = 27 u; O = 16 u.

Find: Formula mass.

Step 1: Count Al = 2 and O = 3.

Step 2: Multiply: Al contribution = 2 × 27 = 54 u; O contribution = 3 × 16 = 48 u.

Step 3: Add: 54 + 48.

Answer: 102 u.

2(b). Calculate the formula mass of MgCl₂.

Given: Mg = 24 u; Cl = 35.5 u.

Step 1: Count Mg = 1 and Cl = 2.

Step 2: Formula mass = 1(24) + 2(35.5).

Step 3: 24 + 71 = 95.

Answer: 95 u.

2(c). Calculate the formula mass of NaCl.

Given: Na = 23 u; Cl = 35.5 u.

Step 1: NaCl contains one Na and one Cl per formula unit.

Step 2: Add their masses: 23 + 35.5.

Answer: 58.5 u.

2(d). Calculate the formula mass of KNO₃.

Given: K = 39 u; N = 14 u; O = 16 u.

Step 1: Count K = 1, N = 1, O = 3.

Step 2: Formula mass = 39 + 14 + 3(16).

Step 3: 39 + 14 + 48 = 101.

Answer: 101 u.

3(a). Calculate the molecular mass of C₂H₅OH.

Given: C = 12 u; H = 1 u; O = 16 u.

Step 1: Count C = 2, H = 5 + 1 = 6 and O = 1.

The H in OH must also be counted.

Step 2: Molecular mass = 2(12) + 6(1) + 16.

Step 3: 24 + 6 + 16 = 46.

Answer: 46 u.

3(b). Calculate the molecular mass of H₂O.

Step 1: Count H = 2 and O = 1.

Step 2: Molecular mass = 2(1) + 16 = 18.

Answer: 18 u.

3(c). Calculate the molecular mass of NH₃.

Step 1: Count N = 1 and H = 3.

Step 2: Molecular mass = 14 + 3(1) = 17.

Answer: 17 u.

3(d). Calculate the molecular mass of CO₂.

Step 1: Count C = 1 and O = 2.

Step 2: Molecular mass = 12 + 2(16) = 44.

Answer: 44 u.

4. How many moles are present in 40 g H₂SO₄?

Given: m = 40 g.

Find: Amount n, in mol.

Step 1: Calculate molar mass.

M = 2(1) + 32 + 4(16)

= 2 + 32 + 64

= 98 g mol⁻¹.

Step 2: Choose the relationship.

n = m/M because a mass must be converted to moles.

Step 3: Substitute with units.

n = 40 g / (98 g mol⁻¹).

Step 4: Calculate.

n = 0.408163… mol.

Answer: Approximately 0.408 mol H₂SO₄.

5(a). Find moles and molecules in 16 g H₂CO₃.

Given: m = 16 g; formula = H₂CO₃.

Find: n and number of molecules, N.

Step 1: Molar mass.

M = 2(1) + 12 + 3(16)

= 2 + 12 + 48

= 62 g mol⁻¹.

Step 2: Convert mass to moles.

n = m/M = 16/62

= 0.258064… mol.

Step 3: Convert moles to molecules.

N = nNA

= (16/62) × 6.02 × 10²³

= 1.5535… × 10²³.

Answers: n ≈ 0.258 mol; N ≈ 1.55 × 10²³ molecules.

The unrounded fraction 16/62 is used in the second calculation to avoid early-rounding error.

5(b). Find moles and molecules in 20 g C₆H₁₂O₆.

Given: m = 20 g; formula = C₆H₁₂O₆.

Find: n and N.

Step 1: Molar mass.

M = 6(12) + 12(1) + 6(16)

= 72 + 12 + 96

= 180 g mol⁻¹.

Step 2: Moles.

n = m/M = 20/180

= 0.111111… mol.

Step 3: Molecules.

N = nNA

= (20/180) × 6.02 × 10²³

= 6.6888… × 10²².

Answers: n ≈ 0.111 mol; N ≈ 6.69 × 10²² molecules.

Test Yourself: Answers

Identify chemistry in your home.

Cooking food, washing with soap, taking medicines, burning fuel and preserving food involve chemistry.

For example, burning fuel is a chemical change, while boiling water is a physical change.

Relate living things to chemistry.

Digestion, respiration and growth depend on chemical reactions.

Respiration includes the cellular processes that release usable energy from food.

Which branch studies the identity and amount of substances?

Analytical chemistry. Qualitative analysis identifies substances; quantitative analysis measures their amounts.

What can a deficiency of biomolecules cause?

A deficiency means an insufficient amount.

Insufficient essential nutrients or required biomolecules can disturb normal body functions and cause disease. The effects depend on which substance is lacking.

Give examples of green chemistry.

Using safer solvents, reducing waste, choosing catalysts and designing energy-efficient processes.

Differentiate medicinal chemistry and biochemistry.

Medicinal chemistry focuses on drug design and development. Biochemistry studies chemical substances and reactions in living organisms.

Differentiate matter and a pure substance.

Matter is anything with mass and volume. It includes both pure substances and mixtures.

A pure substance is matter with fixed chemical composition and characteristic properties.

Name the elements in these compounds.

Compound

Formula

Elements

Washing soda

Na₂CO₃·10H₂O

Sodium, carbon, oxygen, hydrogen

Sucrose

C₁₂H₂₂O₁₁

Carbon, hydrogen, oxygen

Silicon dioxide

SiO₂

Silicon, oxygen

Sodium hydroxide

NaOH

Sodium, oxygen, hydrogen

Classify the materials.

Material

Classification

Reason

Pure sodium chloride

Compound

Na and Cl chemically combined in a fixed ratio

Ice cream

Mixture

Contains several substances

Blood

Mixture

Contains cells and other components in plasma

Silicon

Element

One type of atom

Coca-Cola

Mixture

Contains water and other ingredients

Tin

Element

One type of atom

Zinc

Element

One type of atom

Pure water

Compound

H and O chemically combined in a fixed ratio

Sulfur

Element

One type of atom

Differentiate empirical and molecular formulae.

The empirical formula shows the simplest atom ratio. The molecular formula shows actual atom numbers in a molecule.

For H₂O₂, the ratio 2 : 2 reduces to 1 : 1, giving empirical formula HO.

Why distinguish molecular mass and formula mass?

A molecule is a separate bonded group of atoms. An ionic crystal is a repeating ion lattice.

Molecular mass refers to one molecule; formula mass refers to the composition of one formula unit. Both are obtained by adding the appropriate atomic masses.

Classify the chemical species.

Species

Classification

O₂, N₂, Cl₂, H₂, H₂O

Neutral molecules

H⁺ and Na⁺

Cations

CO₃²⁻

Polyatomic anion

CH₃•

Free radical

Br without a written charge or dot

Neutral bromine atom

A neutral bromine atom itself has an unpaired electron and can be described as a radical when electronic structure is considered. The printed symbol should be read carefully; Br• explicitly indicates the radical.

Justify the classification of molecules.

Use the total number of atoms and whether they belong to the same or different elements.

H₂O contains three atoms from two elements: triatomic and heteroatomic.

O₃ contains three atoms from one element: triatomic and homoatomic.

Balance the potassium chlorate equation using coefficient 4.

Given: 4KClO₃ → 4KCl + O₂.

Left O = 4 × 3 = 12. Each O₂ contains two O atoms, so 12/2 = 6 molecules are required.

4KClO₃ → 4KCl + 6O₂

Divide every coefficient by 2 to get the simplest form:

2KClO₃ → 2KCl + 3O₂.

Balance CaCO₃ + HCl → CaCl₂ + H₂O + CO₂.

CaCl₂ contains two Cl atoms. Put 2 before HCl.

CaCO₃ + 2HCl → CaCl₂ + H₂O + CO₂

Check: Ca = 1, C = 1, O = 3, H = 2 and Cl = 2 on each side.

Relate the mole to Avogadro’s constant.

N = nNA.

For n = 1 mol:

N = 1 mol × 6.02 × 10²³ mol⁻¹

= 6.02 × 10²³ specified entities, using the textbook’s rounded value.

The particle count equals the amount in moles multiplied by the number of particles per mole.

Calculate moles in 30 g H₃PO₄.

Given: m = 30 g. Use H = 1, P = 31 and O = 16.

Find: n.

Step 1: Molar mass.

M = 3(1) + 31 + 4(16)

= 3 + 31 + 64

= 98 g mol⁻¹.

Step 2: Formula.

n = m/M.

Step 3: Substitute.

n = 30/98 = 0.306122… mol.

Answer: Approximately 0.306 mol H₃PO₄.

Quick Revision

Formula sheet

Task

Relationship

Protons

Z

Neutrons

A − Z

Neutral atom electrons

Z

Moles from mass

n = m/M

Mass from moles

m = nM

Specified particles

N = nNA

Moles from particles

n = N/NA

Gas volume at 0°C, 1 atm

V = n × 22.4 L mol⁻¹

Molecular-formula multiplier

Molecular mass / empirical formula mass